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joja [24]
3 years ago
7

A force acting on a body of mass 200g displace it through 200cm in 5s. Find the magnitude of the force if the initial velocity o

f is Zero​
Physics
2 answers:
kow [346]3 years ago
4 0

Answer:

<em><u>F = 0.32 N</u></em>

Explanation:

<em><u>GIVEN:</u></em>

Mass = m =  200 g = 0.2 kg

Distance = S = 200 cm = 2 m

Time = t = 5 s

Initial velocity = U = 0 m/s

<em><u>REQUIRED</u></em>

Force = F = ?

<em><u>SOLUTION</u></em>

Using Second Equation of Motion,

S = Ut + 1/2 at²

2 = (0)(5) + 1/2 a(5)²

2 = 25/2 a

a = 4/25

a = 0.16 m/s²

So,

Acceleration = a = 0.16 m/s²

Now Using Equation from Newtons Second Law of Motion

F = ma

F = (2)(0.16)

<em><u>F = 0.32 N</u></em>

Gnesinka [82]3 years ago
3 0

Answer:

Explanation:A force acting on a particle of mass 200 g displaces it through 400 cm in 2 seconds. Find the magnitude of the force if the initial velocity of the particle is zero ... A steel ball of mass 50 g is thrown vertically downwards with a velocity of 15 ... The weight of the body is 19.6N, the mass of the body is (g=9.8ms−2).

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The new speed of car is 10.9 m/s

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According to the principle of momentum conservation, momentum is only modified by the action of forces as they are outlined by Newton's equations of motion; momentum is never created nor destroyed inside a problem domain.

Mass of the railroad car, m₁ = 7950 kg

Mass of the load, m₂ = 2950 kg

It can be assumed as the speed of the car, u₁ = 15 m/s

Initially, it is at rest, u₂ = 0

Let v is the speed of the car. It can be calculated using the conservation of momentum as :

m_1u_1 + m_2u_2 = (m_1 + m_2) v

v =\frac{m_1u_1}{m_1+m_2}

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v= 10.9 m/s

Therefore, the new speed of care is 10.9 m/s

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2 years ago
Water that flows from behind a large dam can cause machines to produce electricity. What change takes place?
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8 0
3 years ago
URGENTTT PLEASE HELPPPP. You put m1 = 1 kg of ice cooled to -20°C into mass m2 = 1 kg of water at 2°C. Both are in a thermally i
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Answer:

Explanation:

heat lost by water will be used to increase the temperature of  ice

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heat lost = heat gained

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50POINTS! Find the orbital speed of a satellite in a circular orbit 1700km above the surface of the Earth. M_earth 5.97e24kg, r_
ivolga24 [154]
<h2>Answer: 7020.117 m/s</h2>

Explanation:

The velocity of a satellite describing a circular orbit is<u> constant</u> and defined by the following expression:  

V=\sqrt{G\frac{M}{R}} (1)  

Where:  

G=6.674({10}^{-11})\frac{N{m}^{2}}{{kg}^{2}} is the gravity constant

M_{Earth}=5.97{10}^{24}kg the mass of the massive body around which the satellite is orbiting, in this case, the Earth .

R=r_{Earth}+h=8080000m the radius of the orbit (measured from the center of the planet to the satellite).  

This means the radius of the orbit is equal to <u>the sum</u> of the average radius of the Earth r_{Earth} and the altitude of the satellite above the Earth's surface h.

Note this orbital speed, as well as orbital period, does not depend on the mass of the satellite. It depends on the mass of the massive body (the Earth).

Now, rewriting equation (1) with the known values:

V=\sqrt{(6.674({10}^{-11})\frac{N{m}^{2}}{{kg}^{2}})\frac{5.97{10}^{24}kg}{8080000m}}

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