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harkovskaia [24]

2 years ago

15

A car initially miving at 0.5m/s along a track.the car come to rest after travelling 1m.the car is repeated on the same of track

,but car initial moving at 1m/s.How far does the car travel before come to rest?

1 answer:

cluponka [151]2 years ago

6 0

Answer:

it will travel 69 m long consuming. it is totally wrong

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Sam is walking through the park. He hears a police car siren moving on the street coming toward him. What happens to the siren s

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The sound gets louder as it gets closer and when it passes is gets softer

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3 years ago

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A helicopter has blades of length 4.0 m rotating at 3.0 rev/s in a horizontal plane.If the vertical component of the Earth’s mag

VARVARA [1.3K]

Answer:

Induced emf, $\epsilon=9.79\times 10^7\ volts$

Explanation:

Given that,

Length of the helicopter, l = 4 m

Angular speed of the helicopter, $\omega=3\ rev/s=18.84\ rad/s$

The vertical component of the Earth’s magnetic field is, $B=6.5\times 10^5\ T$

We need to find the induced emf between the tip of a blade and the hub. The induced emf in terms of angular velocity of an rotating object is given by :

$\epsilon=\dfrac{1}{2}B\omega l^2$

$\epsilon=\dfrac{1}{2}\times 6.5\times 10^5\times 18.84\times (4)^2$

$\epsilon=9.79\times 10^7\ volts$

So, the induced emf between the tip of a blade and the hub is $\epsilon=9.79\times 10^7\ volts$ . Hence, this is the required solution.

5 0

3 years ago

The graph shows the displacement of a mouse

hram777 [196]

The farthest position the mouse reaches inside the tunnel is 4 meters into the tunnel.

From the graph,

The positions reached after,

5 s = 4 m

10 s = 2 m

20 s = 2 m

35 s = 3 m

40 s = 0 m

So the farthest position here is 4 m into the tunnel.

The rate of change of positions is displacement. So displacement will be change in initial and final positions divided by change in time.

s = Δx / Δt

Therefore, the farthest position the mouse reaches inside the tunnel is 4 meters into the tunnel.

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1 year ago

What is the net force?

aliina [53]

400N ...... fkwnfjfjwjdpgnber

8 0

3 years ago

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A car whose total mass is 800kg travelling with a uniform velocity of 20m/s suddenly observes a stationary dog on it's path 50m

Gelneren [198K]

Answer:

Driver hits the dog

Explanation:

From kinematics equation

$v_f^{2}=v_i^{2}+2as$ and making a the subject

$a=\frac {v_f^{2}-v_i^{2}}{2s}=\frac {0-20^{2}}{2*50}=-4m/s^{2}$

F=ma=800*-4=-3200 N

The driver is required to apply a force of 3200 N to effectively not hit the dog. However, when the driver applies 2000 N, this is less the required force by 1200 N hence the driver hits the dog.

4 0

3 years ago