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harkovskaia [24]
3 years ago
15

A car initially miving at 0.5m/s along a track.the car come to rest after travelling 1m.the car is repeated on the same of track

,but car initial moving at 1m/s.How far does the car travel before come to rest?​
Physics
1 answer:
cluponka [151]3 years ago
6 0

Answer:

it will travel 69 m long consuming. it is totally wrong

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What is the KE of a bicycle with a mass of 41kg traveling at a velocity of 8 m/s ?
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What is the kinetic energy of a bicycle with a mass of 14 kg traveling at a velocity of 3 m/s? Physics ... K=12mv2=12×14 kg × (3 m/s)2=63 Joule.

1 answer  

63 Joule Explanation: K=12mv2=12×14 kg × (3 m/s)2=63 Joule

Explanation:

K=12mv2=12×14 kg × (3 m/s)2=63 Joule.

63 Joule Explanation: K=12mv2=12×14 kg × (3 m/s)2=63 Joule

3 0
3 years ago
Si se deja caer un carrito de una pista de coches sin friccion y su altura inicial es de 1.4 metros, cual es la velocidad maxima
Svet_ta [14]

Answer:

5.241\ \text{m/s}

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m = Masa del coche

g = Aceleración debida a la gravedad = 9.81\ \text{m/s}^2

h = Altura = 1.4\ \text{m}

v = Velocidad del automóvil en la parte inferior de la pista

Aquí asumimos que el automóvil desciende verticalmente. La energía potencial del automóvil se completará convertida en energía cinética en la parte inferior de la pista ya que no hay pérdida de energía.

mgh=\dfrac{1}{2}mv^2\\\Rightarrow v=\sqrt{2gh}\\\Rightarrow v=\sqrt{2\times 9.81\times 1.4}\\\Rightarrow v=5.241\ \text{m/s}

La velocidad máxima que puede alcanzar el coche es 5.241\ \text{m/s}.

8 0
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