<span>let y = sec^2 ( pi x )
y' = 2 sec ( pi x ) sec( pi x ) tan ( pi x ) pi
y' = 2pi sec^2 ( pi x ) tan ( pi x )
y''= 2pi sec^2 ( pi x ) * sec^2 ( pi x ) * pi + 2pi tan ( pi x ) * 2pi sec^2 ( pi x ) tan ( pi x )
y'' = 2 pi^2 sec^4 ( pi x ) + 4 pi^2 sec^2 ( pi x ) tan^2 ( pi x )</span>
Answer:
$560
Step-by-step explanation:
Given that :
Principal, P= $500
Interest rate, r = 12% per year
Amount in account after 1 year
Time = 1 year
Using the relation :
A = P(1 + rt)
A = final amount in account
A = $500(1 + 0.12(1))
A = $500(1 + 0.12)
A = $500(1.12)
A = $560
That would be A, 22/12 and 27/12