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sladkih [1.3K]
3 years ago
12

Sue bought ten items at an average price of $3.60. The cost of eight of the items totaled $30. If the other two items were the s

ame price, what was the price she paid for each ?
1) $15, 2) $7.50, 3) $6, 4) $3, 5) $1.50

I guess the answer is $7.50.
What is yr answer ???
Mathematics
2 answers:
Katen [24]3 years ago
7 0
Ok soo if the 10 items avg $3.60 each then your total for the ten items was $36. if we know that the cost of 8 items is $30 then there is 6 dollars left. nd if we no that the remaining 2 are the same price then each should be $3  
Nina [5.8K]3 years ago
6 0
\frac{30+2x}{10}=3.60\ \ \ \ /\cdot10\\\\30+2x=36\ \ \ \ /-30\\\\2x=6\ \ \ /:2\\\\x=3\ (\$)

Answer:\$3\ (4)
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If a = 0.6 repeating and b = 0.75, then a x b = blank and a/b = blank
atroni [7]

Answer:

a*b = 1/2

a/ b = 8/9

Step-by-step explanation:

a = 0.66666  and b = 0.75

To multiply it we write the decimal numbers in fraction form

a= 0.666666...

Multiply by 10 on both sides

10 a = 6.66666...

    a = 0.66666...

Subtract the second equation

9a = 6

divide by 9 on both sides

a=\frac{6}{9}=\frac{2}{3}

so 0.6666 = 2/3

Now we convert 0.75 into fraction form

0.75=\frac{0.75}{1}

Multiply top and bottom by 100 to remove decimal

\frac{75}{100} = \frac{3}{4}

so 0.75 is 3/4

a= 2/3  and b = 3/4

a*b = \frac{2}{3} * \frac{3}{4} = \frac{6}{12} = \frac{1}{2}

\frac{a}{b} = \frac{\frac{2}{3}}{\frac{3}{4}} = \frac{2}{3} * \frac{4}{3} =\frac{8}{9}


8 0
3 years ago
A stadium has a a central rectangular area 125m long by 80m wide.there are two semi circular ends.a running track goes all the w
Fudgin [204]

a)The total inside length of the curved ends of the track will be 25.13 meters

b)The total distance around the inside of the track will be 275.13 meters

c)The area inside the track is 10050 square meters.

<h3>What is an area?</h3>

The space occupied by any two-dimensional figure in a plane is called the area. The space occupied by the circle in a two-dimensional plane is called the area of the circle.

Given that:-

A stadium has a central rectangular area 125m long by 80m wide. there are two semi-circular ends. a running track goes all the way around.

a) what is the total inside length of the curved ends of the track?

The length of the curved track means it is a perimeter of the circle so the radius of the semicircle will be 4 meters.

So the length will be = π r + πr = 2 πr

                                  = 2 x π x 4 = 25.13

b) what is the total distance around the inside of the track?

The total distance of the track will be the sum of the length of the two semicircles and the longer side of the rectangle.

Total length = 125 + 125 + 25.13

                     = 275.13 meters

c) what is the area inside of the track?

The area will be equal to the area of the two semicircular tracks and the rectangular track.

Total Area = Area of semicircle + Area of semicircle + Area of rectangle

                  = ( π/2 ) r² + (π/2) r² + ( L x W )

                  =  π  r² + (  L x W)

                  = π ( 4 )² + ( 125 x 8 )

                  = 10050.26 square meters.

Therefore the total inside length of the curved ends of the track will be 25.13 meters. The total distance around the inside of the track will be 275.13 meters. The area inside the track is 10050 square meters.

To know more about an area follow

brainly.com/question/25292087

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Step-by-step explanation:

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