<h3>
Answer: P(B) = 7/20</h3>
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Work Shown:
Given info
P(A) = 7/20
P(A∩B)=49/400
P(B) = unknown
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P(A∩B) = P(A)*P(B), assuming A and B are independent events
49/400 = (7/20)*P(B)
(7/20)*P(B) = 49/400
P(B) = (20/7)(49/400)
P(B) = (20*49)/(7*400)
P(B) = (20*7*7)/(7*20*20)
P(B) = 7/20
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Note how
P(A∩B) = P(A)*P(B)
P(A∩B) = (7/20)*(7/20)
P(A∩B) = (7*7)/(20*20)
P(A∩B) = 49/400
which helps to confirm the answer.
For this case, the first thing we must do is define variables:
x: rental charge per day
y: rental charge per mile
We write the system of equations:
3x + 300y = 81
5x + 600y = 145
Solving the system we have:
x = 17
y = 1/10
Answer:
rental charge per day = 17 $
rental charge per mile = 1/10 $
These problems are rather easy. What you need to remember is that the parallel line segments will always contain the same number so the angle (65) on b2 would be the same angle for a2, bt at. so now to find the angle for b1 and a1 so we would subtract 65( the angle for B2) by 180 (the angle for a line) which would come out to be 115.
i hope this helped you, if not heres a link to a website that explains what i tried to explain.
Answer:
your mom
Step-by-step explanation:
Answer:
59/1000
Step-by-step explanation:
Given in the question, the section will follow
<u> Event Number of employees Classification</u>
A 120 Supervisors
B 50 Maintenance
C 1460 Production
D 302 Management
E 68 Secretarial
<u>Total 2000 all employees</u>
Probability that a person selected is in maintenance
P(M)= 50/2000 =1/40
Probability that a person selected in in secretarial
P(S)=68/2000 = 17/500
The probability that the first person selected is either in maintenance or in secretarial you add the two
1/40 + 17/500 = 59/1000
