Using the knowledge in computational language in C++ it is possible to write a code that asks the user to enter two numbers. the program should use the conditional operator to determine which number is the smaller and which is the larger.
<h3>Writting in C++ code:</h3>
#include <iostream>
using namespace std;
int main(){
float a, b;
cout<<"Enter two numbers:";
cin>>a>>b;
if(a>b) {
cout<<"Larger Number:"<<a<<endl;;
cout<<"Smaller Number:"<<b;
}
else if(b<a){
cout<<"Larger Number:"<<b<<endl;
cout<<"Smaller Number:"<<a;
}else{
cout<<"Number are equal!"<<endl;
}
}
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Answer:
1. G=D+(A+C^2)*E/(D+B)^3
cobegin:
p1: (D+B)
p2: p1^3
p3: C^2
p4: A+ p3
p5: E/p2
p6: p4 * p5
p7: D + p6
:G
coend
2. Now The value A=2, B=4, C=5, D=6, and E=8
p1: 6+4 =10
p2: p1 ^3= 10^3= 1000
p3: c^2= 5^2 =25
p4: A + p3= 2 +25 =27
p5: 8/1000
p6: 27 *8/1000
p7: D+ P6= 6+ 216/1000
= 6216/1000
=6.216
Explanation:
The above, first bracket with power is processed, and then power inside and outside bracket. And rest is according to BODMAS, and one process is solved at a time.
Answer:
5 indicators of happiness that might surprise you · Happiness is deep · Happy is busy · Can't buy me happiness · The happiness gene · No regrets.
Explanation:
Try checking if you placed the motherboard in correctly. I am not certain enough.
The correct answer is C) ease of use.
The fact that a web app is written to be run within any of the standard browser and on any platform on which that browser operates is called "ease of use."
The ease of use concept indicates that the product is "amicable" or "friendly" to use by most people because it is not required andy technical knowledge to operate the product. In this case, the app is written to be run within any of the standard browser and on any platform on which that browser operates, so it is "friendly" to operate bu most systems. App's companies and software companies created this "ease of use" concept for many of their products so they can sell most of them because people know they are easy to use and functional.