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Jo and Pete have collected some aluminum cans to be recycled. Pete has 47 pounds of cans and Jo has 52 pounds. They can get $0.2

Ksenya-84 [330]

Answer:

Step-by-step explanation:

Total weight of aluminum cans that Pete collected for recycling is 47 pounds.

Total weight of aluminum cans that Jo collected for recycling is 52 pounds.

They can get $0.21 per pound for the cans. Therefore,

The total amount that Pete will get for collecting 47 pounds of aluminum would be

0.21 × 47 = $9.87

The total amount that Jo will get for collecting 52 pounds of aluminum would be

0.21 × 52 = $10.92

The total amount of money that they would get is

9.87 + 10.92 = $20.79

3 0

2 years ago

What is n? 12^2+n^2=(n+2)^2

Law Incorporation [45]

Answer:

n=35

Step-by-step explanation:

Isolate the variable by dividing each side by factors that don't contain the variable

4 0

2 years ago

Nike claims that the number of miles a jogger can get a on a pair of Nike’s running shoes is higher than 1000. Moreover, Nike al

Lisa [10]

Answer:

a) There is statistical evidence showing that Nike shoues get more than 1000 miles.

b) The p-value of t=1.84 and df=149 is P=0.034.

It represents the probability of getting this sample results if the population parameters are the ones from the null hypothesis.

In this case, the low p-value shows is rare to get a sample of n=150 and mean 1015 miles, if the population mean is 1000. This is evidence that the null hypothesis is not true.

c) There is no enough evidence to claim that Nike shoes outperform Adidas shoes by 15 miles.

d) The p-value for t=0.55 and 318 df is P=0.29.

This shows that there is a probability of P=0.29 of getting samples that show this difference if the statement of the null hypothesis is true.

Step-by-step explanation:

a) We have to perform a hypothesis test with the following hypothesis:

$H_0: \mu\leq 1000\\\\H_a: \mu>1000$

The level of significance is 0.05.

The sample mean is 1015 and the sample standard deviation is 100.

The degrees of freedom are df = 150-1 = 149.

The t-statistic is:

$t=\frac{M-\mu}{s/\sqrt{n}}=\frac{1015-1000}{100/\sqrt{150}} =\frac{15}{8.165} =1.84$

The critical value for t is t=1.66. As the t-statistic is bigger than the critical t, it falls in the rejection region. The null hypothesis is rejected.

There is statistical evidence showing that Nike shoues get more than 1000 miles.

b) The p-value of t=1.84 and df=149 is P=0.034.

It represents the probability of getting this sample results if the population parameters are the ones from the null hypothesis.

In this case, the low p-value shows is rare to get a sample of n=150 and mean 1015 miles, if the population mean is 1000. This is evidence that the null hypothesis is not true.

c) In this case, the null and alternative hypothesis are:

$H_0: \mu_1-\mu_2\leq 15\\\\H_a: \mu_1-\mu_2>15$