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Elan Coil [88]
3 years ago
6

Solve the inequality and graph the solution on the line provided.

Mathematics
1 answer:
mel-nik [20]3 years ago
7 0
4x>13+3
4x>16 /4
X> 4
Hope it’s help

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5/3 or 10/12

Step-by-step explanation:

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Need help with this question!!!<br> Pls explain!!!<br><br> 3=-(4x+7)+3x
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The answer would be, x = 10

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Mr. Smith wishes to retire in 16 years. When he retires he would like to have $500,000 in his bank account. Mr. Smith's bank pay
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The amount he should deposit is 31,250 dollars
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3 years ago
Joan has 1/2 yard of felt. She will use 1/3 of it to make place cards. How much felt will she will use for place cards?
-Dominant- [34]
ANSWER


\frac{1}{6}  \: yards

EXPLANATION

It was given that, Joan has


\frac{1}{2} \:  yard \: of \: felt

and she will use

\frac{1}{3}
of it to make place cards.


We want to find how felt she will use for place cards.


We just have to find,

=  \frac{1}{3}  \: of \:  \frac{1}{2}



=  \frac{1}{3}  \times  \frac{1}{2}


=  \frac{1}{6}

Therefore Joan will use

\frac{1}{6}


yards of felt for the place cards.
7 0
2 years ago
You have 100 cm of string which can be cut in one place (or not cut at all) and then formed into a circle and a square (or just
Ne4ueva [31]

Answer:

44cm for minimum area and 0 for maximum area (circle)

Step-by-step explanation:

Let's C be the circumference of the circle and S be the circumference of the square. If we cut the string into 2 pieces the total circumferences would be the string length 100cm.

S + C  = 100 or S = 100 - C

The side of square is S/4 and radius of the circle is \frac{C}{2\pi}

So the area of the square is

A_S = \frac{S^2}{4^2} = \frac{S^2}{16}

A_C = \pi\frac{C^2}{(2\pi)^2} = \frac{C^2}{4\pi}

Therefore the total area is

A = A_S + A_C = \frac{S^2}{16} + \frac{C^2}{4\pi}

We can substitute 100 - C for S

A = \frac{(100 - C)^2}{16} + \frac{C^2}{4\pi}

A = \frac{100^2 - 200C + C^2}{16} + \frac{C^2}{4\pi}

A = 625 -12.5C + \frac{C^2}{16} + \frac{C^2}{4\pi}

A = 625 -12.5C + C^2(\frac{1}{16} + \frac{1}{4\pi})

To find the maximum and minimum of this, we can take the first derivative and set that to 0

A^{'} = -12.5 + 2C(\frac{1}{16} + \frac{1}{4\pi}) = 0

C(\frac{1}{8} + \frac{1}{2\pi}) = 12.5

C \approx 44 cm

If we take the 2nd derivative:

A^{''} = \frac{1}{8} + \frac{1}{2\pi} > 0

We can see that this is positive, so our cut at 44 cm would yield the minimum area.

The maximum area would be where you not cut anything and use the total string length to use for either square or circle

if C = 100 then A_C = \frac{C^2}{4\pi} = \frac{100^2}{4\pi} = 795.77 cm^2

if S = 100 then A_S = \frac{S^2}{16} = \frac{100^2}{16} = 625 cm^2

So to yield maximum area, you should not cut at all and use the whole string to form a circle

4 0
3 years ago
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