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Ilya [14]
3 years ago
10

Help I need help on a find the x 4x + 16=

Mathematics
1 answer:
sweet-ann [11.9K]3 years ago
3 0

i wanna say its 20x i think

But i hated this!

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PLZZZ HELP ME 50 POINTS PLZZ
Vesna [10]

Answer:

-4

Step-by-step explanation:

In the Whisker-Box plot, the Lower Quartile can be found by the end of the left side of the box. In this case, it is directly above the -4, and so is your answer.

~

*See attached picture.

8 0
3 years ago
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Rewrite the expression with rational exponents as a radical expression.
CaHeK987 [17]

Answer:

7\sqrt[3]{x^2}

Step-by-step explanation:

The rule of exponents that dictates this to be solved is:

x^{\frac{a}{b}}=\sqrt[b]{x^a}

The power of 2/3 is on "x", NOT 7, so we use this property to write it as:

x^{\frac{a}{b}}=\sqrt[b]{x^a} \\7x^{\frac{2}{3}}=7\sqrt[3]{x^2}

third answer choice is right,  7\sqrt[3]{x^2}

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3 years ago
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(Complete the steps in dividing mixed numbers.)
Fed [463]

Answer:

WHAT THE WHAT

Step-by-step explanation:

8 0
3 years ago
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Could someone please help me with this. You will be awarded 15 points!
Crazy boy [7]

Answer:

The answer is A

5 0
3 years ago
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The ideal width of a certain conveyor belt for a manufacturing plant is 50 in. Conveyor belts can vary from the ideal width by a
Gennadij [26K]
<h3><u>Answer:</u></h3>

The answer is:

|x-50|\leq \dfrac{7}{32}

49\dfrac{25}{32}\leq x\leq 50\dfrac{7}{32}

<h3><u>Step-by-step explanation:</u></h3>

The ideal  width of a certain conveyor belt for a manufacturing plant is 50 in.

Conveyor belts can vary from the ideal width by at most 7/32 in.

i.e. the absolute change in the width has to be less than or equal to 7/32 in. and it can't exceed more than that.

That is if it will decrease than the  the acceptable width for the conveyor belt is represented by the expression;

|x-50|\leq \dfrac{7}{32}

Also on solving it we get:

\dfrac{-7}{32}\leq x-50\leq \dfrac{7}{32}\\\\\\50-\dfrac{7}{2}\leq x\leq 50+\dfrac{7}{2}\\\\49\dfrac{25}{32}\leq x\leq 50\dfrac{7}{32}

Hence, the correct choices are:

|x-50|\leq \dfrac{7}{32}

49\dfrac{25}{32}\leq x\leq 50\dfrac{7}{32}

7 0
3 years ago
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