The volume of the sample after the reaction : V₂=5.484 L
<h3>Further explanation</h3>
Given
Reaction
2HBr(g) + Cl2(g) => 2HCl (g)+Br2(g)
0.1100 mol of HBr(g)
5x10⁻² mol of Cl2(g)
Required
The volume of the sample after reaction
Solution
Find limiting reactant :
0.11/2 : 0.05/1 = 0.055 : 0.05
Limiting reactant : Cl₂
mol Products based on mol Cl₂
mol products = mol HCl + mol Br₂
mol products = 2/1x0.05 + 1/1x0.05
mol products = 3 x 0.05 = 0.15
mol reactants = 0.11 + 0.05 = 0.16
<em>From Avogadro's law, </em>
In the same T, P, and V, the gas contains the same number of molecules
So the ratio of gas volume will be equal to the ratio of gas moles
V₁/n₁=V₂/n₂
1 = reactants, 2 = products
Input the value :
5.85/0.16=V₂/0.15
V₂=5.484 L
Answer: Noble gases
Explanation:
Electronegativity is the ability of an atom to gain an electron. Noble gases already have 8 electrons, so they don’t need to gain electrons. If they don’t gain electrons, it has no electronegativity.
Answer: The correct answer is -297 kJ.
Explanation:
To solve this problem, we want to modify each of the equations given to get the equation at the bottom of the photo. To do this, we realize that we need SO2 on the right side of the equation (as a product). This lets us know that we must reverse the first equation. This gives us:
2SO3 —> O2 + 2SO2 (196 kJ)
Remember that we take the opposite of the enthalpy change (reverse the sign) when we reverse the equation.
Now, both equations have double the coefficients that we would like (for example, there is 2S in the second equation when we need only S). This means we should multiply each equation (and their enthalpy changes) by 1/2. This gives us:
SO3 —>1/2O2 + SO2 (98 kJ)
S + 3/2O2 —> SO3 (-395 kJ)
Now, we add the two equations together. Notice that the SO3 in the reactants in the first equation and the SO3 in the products of the second equation cancel. Also note that O2 is present on both sides of the equation, so we must subtract 3/2 - 1/2, giving us a net 1O2 on the left side of the equation.
S + O2 —> SO2
Now, we must add the enthalpies together to get our final answer.
-395 kJ + 98 kJ = -297 kJ
Hope this helps!