Based on the question, it is evident that this question rests on the premise of Charle's Law, which essentially states that temperature is proportional to volume once pressure and mass remain constant.
Thus by Charle's Equation:

Since the initial volume = 2.2 L; the initial temperature = 20 C; and the final volume = 2.6 L,
then V₁ = 2.2 L; T₁ = 20 C; V₂ = 2.6 L and what we would be
finding is T₂ (the final/new temperature)
Now,
⇒

⇒
∴ the new temperature is ≈ 23.6 °C
Answer:
compaction and cementation
Explanation:
The balanced equation is 2H2+O2=2H2O i think
<h3>
Answer:</h3>
266.325 g
<h3>
Explanation:</h3>
We are given the balanced equation;
2NaOH + H₂SO₄ → H₂O + Na₂SO₄
We are required to determine the mass of Na₂SO₄ that will be formed.
<h3>Step 1: Determine the number of moles of NaOH</h3>
Moles = Mass ÷ molar mass
Molar mass of NaOH is 40.0 g/mol
Therefore;
Moles of NaOH = 150 g ÷ 40 g/mol
= 3.75 moles
<h3>Step 2: Determine the number of moles of sodium sulfate formed</h3>
- From the equation 2 moles of NaOH reacts with sulfuric acid to form 1 mole of sodium sulfate.
- Therefore; mole ratio of NaOH : Na₂SO₄ is 2 : 1
Thus, moles of Na₂SO₄ = Moles of NaOH ÷ 2
= 3.75 moles ÷ 2
= 1.875 moles
<h3>Step 3: Determine the mass of Na₂SO₄ produced.</h3>
we know that;
Mass = Moles × Molar mass
Molar mass of Na₂SO₄ is 142.04 g/mol
Therefore;
Mass of Na₂SO₄ = 1.875 moles × 142.04 g/mol
= 266.325 g
Thus, the mass of sodium sulfate formed 266.325 g