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MrMuchimi
3 years ago
8

An obese man was discovered in his air-conditioned hotel room sitting in a chair in front of the television. The air conditioner

was set for 65 degrees Fahrenheit. When the coroner arrived, the man’s body exhibited rigor in his upper body only. estimate how long he has been deceased
Chemistry
1 answer:
Leno4ka [110]3 years ago
8 0

Answer:

It has been approximately 6 hours after death.

Explanation:

This is because between 2-6 hours after death, the body starts becoming stiff from top to bottom, then spreading to the limbs. Since there is only rigor in his upper body, that would mean that with normal temperature and body conditions, it would be 4 or 5 hours after death. But since he is obese and in cold temperature, there is slower progression of rigor, leading to the maximum time in the first rigor mortis phase, 6 hours.

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A mixture of He, Ne, and N2 gases has a pressure of 1.943 atm. If the pressures of He and Ne are 0.137 atm and 0.566 atm, respec
Ad libitum [116K]

Answer:

The parcial pressure of N₂ in the mixture is 1.24 atm.

Explanation:

The pressure exerted by a particular gas in a mixture is known as its partial pressure. So, Dalton's law states that the total pressure of a gas mixture is equal to the sum of the pressures that each gas would exert if it were alone:

PT = PA + PB

This relationship is due to the assumption that there are no attractive forces between the gases.

In this case:

PT=PHe + PNe + PN₂

You know:

  • PT= 1.943 atm
  • PHe= 0.137 atm
  • PNe= 0.566 atm
  • PN₂= ?

Replacing:

1.943 atm= 0.137 atm + 0.566 atm + PN₂

Solving:

1.943 atm= 0.703 atm + PN₂

1.943 atm - 0.703 atm= PN₂

1.24 atm= PN₂

<u><em>The parcial pressure of N₂ in the mixture is 1.24 atm.</em></u>

4 0
2 years ago
How much heat, in kJ, will be absorbed by a 25.0 g piece of aluminum (specific heat = 0.930 J/g・°C) as it changes temperature fr
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Answer:

quantity of heat=mc*theta

=25*0.930(76-25)

=25*0.930*51

=1185.75J

=11.9kJ

4 0
3 years ago
Which is NOT a physical property?
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ability to combine with oxygen

4 0
3 years ago
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Heat never travels from a cooler object to a warmer object.
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I would say False.

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How many grams of sodium acetate ( molar mass = 83.06 g/mol ) must be added to 1.00 Liter of a 0.200 M acetic acid solution to m
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<u>Answer:</u> The mass of sodium acetate that must be added is 30.23 grams

<u>Explanation:</u>

To calculate the number of moles for given molarity, we use the equation:

\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}

Molarity of acetic acid solution = 0.200 M

Volume of solution = 1 L

Putting values in above equation, we get:

0.200M=\frac{\text{Moles of acetic acid}}{1L}\\\\\text{Moles of acetic acid}=(0.200mol/L\times 1L)=0.200mol

To calculate the pH of acidic buffer, we use the equation given by Henderson Hasselbalch:

pH=pK_a+\log(\frac{[\text{salt}]}{[\text{acid}]})  

pH=pK_a+\log(\frac{[CH_3COONa]}{[CH_3COOH]})

We are given:

pK_a = negative logarithm of acid dissociation constant of acetic acid = 4.74

[CH_3COONa]=?mol  

[CH_3COOH]=0.200mol

pH = 5.00

Putting values in above equation, we get:

5=4.74+\log(\frac{[CH_3COONa]}{0.200})

[CH_3COONa]=0.364mol

To calculate the mass of sodium acetate for given number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Molar mass of sodium acetate = 83.06 g/mol

Moles of sodium acetate = 0.364 moles

Putting values in above equation, we get:

0.364mol=\frac{\text{Mass of sodium acetate}}{83.06g/mol}\\\\\text{Mass of sodium acetate}=(0.364mol\times 83.06g/mol)=30.23g

Hence, the mass of sodium acetate that must be added is 30.23 grams

7 0
3 years ago
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