Half-life (period)
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Answer:
Legend has it that Mendeleev conceived and created his table in a single day: February 17, 1869, on the Russian calendar (March 1 in most of the rest of the world).READ THE EXPLANATION
Explanation:
La leyenda dice que Mendeleev concibió y creó su mesa en un solo día: 17 de febrero de 1869, en el calendario ruso (1 de marzo en la mayoría del resto del mundo).
Explanation:
Density of a substance is given by the mass of the substance divided by the volume of the substance .
Hence , d = m / V
V = volume
m = mass ,
d = density ,
From the question , The density of ethylene glycol = 1.11 g / cm³
The unit 1 cm³ = 1 mL
Hence , density = 1.11 g / mL
( a )
The volume of ethylene glycol = 376 mL
The mass of ethylene glycol can be calculated by using the above formula -
d = m / V
m = d * V
m = 1.11 g / mL * 376 mL
m = 417.36 g
( b )
The mass of ethylene glycol = 3.10 Kg
( since , 1 Kg = 1000 g )
The mass of ethylene glycol = 3.10 Kg = 3.10 * 1000 = 3100 g
The Volume of ethylene glycol can be calculated by using the above formula -
d = m / V
V = m / d
V = 3100 g / 1.11 g / mL
V = 2792.79 mL = 2.79279 L
( since , 1 ml = 1/1000 L )
It's also called a continental<span> plate, convergent or divergent boundary, or c</span>ontinental<span> drift.</span>
Answer:
0.5 mole of H₂.
Explanation:
We'll begin by calculating the number of mole in 23 g of Na. This can be obtained as follow:
Mass of Na = 23 g
Molar mass of Na = 23 g/mol
Mole of Na =?
Mole = mass / Molar mass
Mole of Na = 23 / 23
Mole of Na = 1 mole
Next, the balanced equation for the reaction.
2Na + 2H₂O —> 2NaOH + H₂
From the balanced equation above,
2 moles of Na reacted to produce 1 mole H₂.
Finally, we shall determine the number of mole of H₂ produced by the reaction of 23 g (i.e 1 mole) of Na. This can be obtained as follow:
From the balanced equation above,
2 moles of Na reacted to produce 1 mole H₂.
Therefore, 1 mole of Na will react to produce = (1 × 1) / 2 = 0.5 mole of H₂.
Thus, 0.5 mole of H₂ is obtained from the reaction.