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3 years ago

I need help again sorry peoples

Mathematics

1 answer:

Gre4nikov [31]3 years ago

5 0

Answer:

A = (q + z / 2)m

Step-by-step explanation:

9 + z / 2 . m =A

(q + z)m / 2 = A

(q + z)m/2 / m = A / m

2(q + z / 2) = 2(a / m)

Simplify Left:

q + z = 2(a / m)

Simplify right:

q + z = 2A / m

Subtract z from both sides

q = 2A / m -z

A = (q + z / 2)m

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A high speed machine makes 108 bolts every minute. How long does the machine take to make 18 bolts?

d1i1m1o1n [39]

Answer:

about 9 seconds

Step-by-step explanation:

18x60/108

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3 years ago

Combine terms: 12a + 26b -4b – 16a.

Liula [17]

Answer:

C. -4a + 22b

Step-by-step explanation:

12a + 26b -4b – 16a

= 12a – 16a + 26b – 4b

= -4a + 22b

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3 years ago

Read 2 more answers

Please Help? A circle has an arc length of 5π in. The central angle for this arc measures π/3 radians. What is the area of the a

Zielflug [23.3K]

Answer:

The area of the associated sector is $\frac{25}{24}\pi \ in^{2}$

Step-by-step explanation:

step 1

Find the radius of the circle

we know that

The circumference of a circle is equal to

$C=2\pi r$

we have

$C=5\pi\ in$

substitute and solve for r

$5\pi=2\pi r$

$r=2.5\ in$

step 2

Find the area of the circle

we know that

The area of the circle is equal to

$A=\pi r^{2}$

we have

$r=2.5\ in$

substitute

$A=\pi (2.5^{2})=6.25\pi\ in^{2}$

step 3

Find the area of the associated sector

we know that

$2\pi\ radians$ subtends the complete circle of area $6.25\pi\ in^{2}$

by proportion

Find the area of a sector with a central angle of $\pi/3\ radians$

$\frac{6.25\pi }{2\pi} =\frac{x}{\pi/3}\\x=6.25*(\pi/3)/2\\ \\x=\frac{25}{24}\pi \ in^{2}$

8 0

4 years ago

PLEASE ANSWER! URGENT

Lorico [155]

There would be 2034 students competing in 2012.

We can write a simple equation to find this answer. Let X, be the number of students starting in 2012. Then, we multiply by 0.9 and 1.1 to get to 2014. To work backwards, just divide by 1.1, then by 0.9.

2014 / 1.1 / 0.9 = 2034

4 0

3 years ago

Determine if the following relations are functions. if they are functions, also state the domain and range.

Feliz [49]

Answer:

no, they are not functions

Step-by-step explanation:

this is because a single domain has multiple range.

i.e. domain 2 has ranges 2 and 4

4 0

3 years ago