Answer:
Look in the file, I've drew it there!
8x12=96 4x34=136 136+96=232 232/2=116 answer=116
Answer:
The remaining liquid has a volume of 345.4 cm³.
Step-by-step explanation:
To solve this question we first need to calculate the volume of each container.
Cylindrical:
Volume = h*pi*r² = 14*3.14*(5)² = 1099 cm³
Cone:
Volume = (1/3)*h*pi*r² = (1/3)*20*3.14*(6)² = 753.6 cm³
Since the liquid from the cylinder was transfered to the cone until the latter was full, then what remains in the cylinder is it's original volume minus the cone volume. So we have:
remaining liquid = 1099 - 753.6 = 345.4 cm³
Answer:
Step by Step
This is probably the most difficult problem in elementary Geometry. I stopped counting after about 20 steps. The trick is to follow a very carefully constructed diagram which looks simple enough until you start using it.
Givens
- Triangle ABC with 2 equal sides AB and AC.
- BC is the third side and is not equal to either of the other 2.