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jarptica [38.1K]
3 years ago
9

How many solutions does the equation 4p + 7 = 3 + 4 + 4p have?

Mathematics
1 answer:
KatRina [158]3 years ago
3 0

Let's solve the given equation to get the answer.

4p + 7 = 3 + 4 + 4p

4p+7=7+4p By simplifying.

4p+7-4p=7+4p-4p By subtracting 4p from each sides.

7=7

From the above result notice that p has vanish and we are left with 7=7.

So, there is infinitely many solutions.

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The length of a rectangle is 3 m less than twice the width if the area of the rectangle is 66 5 m² find the dimensions
goblinko [34]

Let the width be x.

Then,Length = ( 2x - 3 ) m

<u>According to the question, </u>

Area of rectangle = 665 m² [ Given ]

Formula: Area of rectangle = Length × Width

\sf \implies \: length \:  \times breadth = 665 \: m {}^{2}

\sf\implies \: (2x - 3) \times x = 665

\sf \implies \: 2 {x}^{2}  - 3x = 665

\sf \implies \:  {2x}^{2}  - 3x - 665 = 0

<u>By split middle term </u>

\sf \implies \: 2 {x}^{2}  - 38x  + 35x - 665 = 0

\sf\implies \: 2x(x - 19) + 35(x - 19) = 0

\sf \implies \: (2x + 35) = 0 \: or \: (x  - 19) = 0

\sf \implies \: x =  \dfrac{ - 35}{2}  \: or \:  \: x = 19 \:

Note: Ignore negative number.

Now,

Width of a rectangle = 19 m

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