The average speed of Joshua during that time is 2500 m/h.
Explanation:
It is given that Joshua started cycling at 5:15 pm. By 8:09 pm he has covered a distance of 7250 m.
The total time taken by Joshua from 5:15 pm to 8:09 pm is
Dividing we get,
Adding, we have,
Thus, the total time taken by Joshua is
To determine the average speed we use the formula,
where and
Hence, substituting the values we have,
Dividing, we get,
Thus, the average speed of Joshua during that time is 2500 m/h.
Answer:
rate = natural log (Total / Principal) / Years
We need 5,000 to become 10,000 in 10 years so,
rate = natural log (Total / Principal) / Years
rate = natural log(10,000 / 5,000) / 10
rate = natural log(2) / 10
rate = 0.69314718056 / 10
rate = .069314718056 which equals
rate = 6.9314718056 per cent
Source: https://www.1728.org/rate2.htm
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Step-by-step explanation:
The general form of a solution of the differential equation is already provided for us:
where . We now want to find a solution
such that
and
. Therefore, all we need to do is find the constants
and
that satisfy the initial conditions. For the first condition, we have:
For the second condition, we need to find the derivative first. In this case, we have:
Therefore:
This means that we must solve the following system of equations:
If we add the equations above, we get:
If we now substitute into either of the equations in the system, we get:
This means that the solution obeying the initial conditions is:
Indeed, we can see that:
which do correspond to the desired initial conditions.