Point J' would be located at (5,0)
R; all quadratic functions are going to have ranges and domains of *ALL REAL NUMBERS*.
Answer:
Step-by-step explanation:
Simplifying
2m + -6n + 5n + 3m = 0
Reorder the terms:
2m + 3m + -6n + 5n = 0
Combine like terms: 2m + 3m = 5m
5m + -6n + 5n = 0
Combine like terms: -6n + 5n = -1n
5m + -1n = 0
Solving
5m + -1n = 0
Solving for variable 'm'.
Move all terms containing m to the left, all other terms to the right.
Add 'n' to each side of the equation.
5m + -1n + n = 0 + n
Combine like terms: -1n + n = 0
5m + 0 = 0 + n
5m = 0 + n
Remove the zero:
5m = n
Divide each side by '5'.
m = 0.2n
Simplifying
m = 0.2n
Answer:
0.25
Step-by-step explanation: