What is the interquartile range of this data set? 2,5,9,11,18,30,42,55,58,73,81
Tcecarenko [31]
Answer:
I think it's 49 I'm sry if I'm wrong hope you luck
Step-by-step explanation:
Answer:
The least number of stamps required is 
Step-by-step explanation:
Let the number of 
cent stamps be 
and 
cent stamps be 
We have
The minimum number is obtained when more cent stamps are used
Here cannot be greater than 
since 
Substitute 
Not possible since is not a fraction
Substitute 
Not possible since is not a fraction
Substitute 
Possible
Hence minimum number of stamps is
Answer:the car was traveling at a speed of 80 ft/s when the brakes were first applied.
Step-by-step explanation:
The car braked with a constant deceleration of 16ft/s^2. This is a negative acceleration. Therefore,
a = - 16ft/s^2
While decelerating, the car produced skid marks measuring 200 feet before coming to a stop.
This means that it travelled a distance,
s = 200 feet
We want to determine how fast the car was traveling (in ft/s) when the brakes were first applied. This is the car's initial velocity, u.
Since the car came to a stop, its final velocity, v = 0
Applying Newton's equation of motion,
v^2 = u^2 + 2as
0 = u^2 - 2 × 16 × 200
u^2 = 6400
u = √6400
u = 80 ft/s
Answer:
C
Step-by-step explanation:
1 1/4 = 1.25
1 4/5 = 1.8
1.8+1.25=3.05=3 1/20
Answer:
21x - 9
Step-by-step explanation:
