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Anna007 [38]
3 years ago
11

e="\frac{1}{x^2+3x-4} - \frac{1}{x^2-3x+2}" alt="\frac{1}{x^2+3x-4} - \frac{1}{x^2-3x+2}" align="absmiddle" class="latex-formula">
\frac{3}{x^2-4} - \frac{x+5}{x+2}
Mathematics
1 answer:
Andrews [41]3 years ago
4 0
The first one is \frac{-6}{(x-2)(x+4)(x-1)} and the second one is \frac{-x^2-3x+13}{(x+2)(x-2)};; it's tricky because the denominators aren't the same. You have to factor all of the denominators and multiply only the expressions that the other numbers are missing.

The first expression would be factored into \frac{1}{(x+4)(x-1)}- \frac{1}{(x-2)(x-1)}. Multiply (x-2) to the left side and (x+4) to the right, since those are the values the denominator is missing. This results in \frac{x-2}{(x-2)(x+4)(x-1)} - \frac{x+4}{(x-2)(x+4)(x-1)}. When simplified, the answer would be \frac{-6}{(x-2)(x+4)(x-1)}.

The second one would be factored as \frac{3}{(x+2)(x-2)} - \frac{x+5}{x+2}. Like the first one, multiply the missing value to the right side, (x-2), and simplify, resulting in \frac{-x^2-3x+13}{(x+2)(x-2)}.
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How would I use factoring to write equivalent expressions for the following expressions?
Sedbober [7]

Answer:

4(a + 6)

3(x - 4)

Step-by-step explanation:

Factoring is just rewriting an expression into the parts that multiply together to make the original...like if I had a 100 but decided instead to write 4×25 or if I had 25x I wrote 5(5x) .

If you look at your

4a + 24

You're looking for whatever is the same in both pieces (the 4a and also the 24) So there is a 4 in 4a and there is also a 4 "in" 24 (as in 4×6 is 24)

So if you pull out that 4 and throw it up front, whatever is left behind goes into a pair of parentheses.

4 (____ + ____)

4(a + 6)

This is your factored form bc if you multiply that 4 back in you'll get the original expression back again.

4a + 24

= 4(a + 6)

It's like factoring is "un-distributive" property.

Theres a 3 in 3x and also in 12

3x - 12

= 3(x - 4)

6 0
2 years ago
What is the domain of y=log5x
aliina [53]
The answer is both all real numbers less than 0 and all real numbers greater than 0
3 0
3 years ago
Read 2 more answers
An order is written for 1200 adult weight 164 pounds and is 5/9 all with a BSA of 1.9 m to the physician ordered o n c o v i n 2
Kaylis [27]

Answer:

The volume per dose that the patient should receive is 3.8 ml

Step-by-step explanation:

The physician ordered oncovin 2 mg/m² for chemotherapy treatment of a malignant tumor.

The adult's BSA (Body surface area) = 1.9m²

Hence, the amount of oncovin needed based on his body weight is:

2mg/1 m² = x mg/1.9m²

Cross Multiply

x mg = 2mg × 1.9

x = 3.8mg

We are told , oncovin is supplied:1 mg/ml

Hence:

This means

1 mg = 1 ml

3.8 mg = x ml

Cross Multiply

x ml = 3.8 ml

The volume per dose that the patient should receive is 3.8 ml

5 0
3 years ago
Someone please help me with these 2 problems :(
k0ka [10]
If the discriminant b^2-4ac is 0, then you have TWO EQUAL, REAL ROOTS.

If you're given the x-intercepts, you can determine the factors of the polynomial as follows:   Take -3, change the sign and write (x+3).  Take 5, change the sign and write (x-5).  Then the eq'n of the parabola is

f(x) = (x+3)(x-5) = x^2 - 2x -15, in which a=1, b = -2 and c= -15.

You can find the x-coordinate of the vertex, which is also the equation of the axis of symmetry, using

x= -b / (2a).    Here, x = -(-2) / (2[1]), or  x = 1

Find the y-coordinate by subbing 1 for x in the equation above:

y = (1)^2 - 2(1) - 15  =  1 - 2 - 15  =  -16

The vertex is at (1, -16) and the equation of the axis of symm. is x = 1.
7 0
3 years ago
Y + 4x = -1
Georgia [21]
Hope this helps

3,-13
-1,3
0,-1
3,-13
7 0
3 years ago
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