Answer:
The acceleration of the snowball is 0.3125
Explanation:
The initial speed of the snowball up the hill, u = 0
The speed the snowball reaches, v = 5 m/s
The length of the hill, s = 40 m
The equation of motion of the snowball given the above parameters is therefore;
v² = u² + 2·a·s
Where;
a = The acceleration of the snowball
Plugging in the values, we have;
5² = 0² + 2 × a × 40
∴ 2 × 40 × a = 5² = 25
80 × a = 25
a = 25/80 = 5/16
a = The acceleration of the snowball = 5/16 m/s².
The acceleration of the snowball = 5/16 m/s² = 0.3125 m/s² .
Answer:
Basically, at these speeds, the car will, at random times, swerve a bit to one side or the other as if hit by some huge wind (even on the calmest of days). It doesn't happen at slower speeds driving mechanically identical cars, managed to accelerate to a formidable 150 mph and stay there for most of the journey, shifting to higher gears and remaining.
Hope this helped you!
Explanation:
A red racecar accelrates at a constant rate of 5 m/s2. How much time does it take to increase its speed from 50 m/s to 60 m/s?
A.17 s
B.0.058 s
C.0.25 s
D.2.0 s
