Answer: The net force acting on the car 1,299.3 N.
Explanation:
Mass of the car = 710 kg
Initial velocity of the car of the ,u= 37 km/h= 10.27 m/s 
Final velocity of the car,v = 120 km/h = 33.33 m/s
time taken b y car = 12.6 sec
v-u=at
The net force acting on the car 1,299.3 N.
Here we have to add the two measurements given in the question
The measurement values are given as 1.0090 cm and 0.02 cm.we have to add them on the basis of significant figure rules.
As per the addition rule in terms of significant figures
1-First we have to select the number of significant digits after the decimal point of each quantity.
2-Now we have to remember that during the addition ,the resultant of two quantities will follow the quantity having least number of significant figures after the decimal point.
3-Here we are considering the minimum number of significant figures after the decimal points not the minimum number of significant figures in case of multiplication and division
Now we have to add these two quantities as per the above rule-
1.0090 cm +0.02 cm
=1.0290 cm
Here the result will follow 0.02 which has minimum number of significant figures after the decimal points.
Hence we have to round off the number from 9 of 1.0290
As 9 is greater than 5 ,so he actual result will be 1.03 cm
Charge is actually either excessive number or electrons or shortage of them.
as you can't destroy the electron or create it - you can't destroy or create charge
Answer:
39.375 A
Explanation:
To find the induced current, we use the relation
e = -ΔΦ/Δt, where
ΔΦ = change in magnetic flux of the bracelet
Δt = change in time, = 20 ms
Also, Φ = A.ΔB, such that
A = area of the bracelet, 0.005m²
ΔB = magnetic field strength of the bracelet = 1.35 - 4.5 = -3.15 T
ΔΦ = A.ΔB
ΔΦ = 0.005 * -3.15
ΔΦ = -.01575 wb
e = -ΔΦ/Δt
e = -0.01575 / 20*10^-3
e = 0.7875 V
From the question, the resistance of the bracelet is 0.02 ohm, so
From Ohms Law, I = V/R
I = 0.7875 / 0.02
I = 39.375 A
<span>k = 1.7 x 10^5 kg/s^2
Player mass = 69 kg
Hooke's law states
F = kX
where
F = Force
k = spring constant
X = deflection
So let's solve for k, the substitute the known values and calculate. Don't forget the local gravitational acceleration.
F = kX
F/X = k
115 kg* 9.8 m/s^2 / 0.65 cm
= 115 kg* 9.8 m/s^2 / 0.0065 m
= 1127 kg*m/s^2 / 0.0065 m
= 173384.6154 kg/s^2
Rounding to 2 significant figures gives 1.7 x 10^5 kg/s^2
Since Hooke's law is a linear relationship, we could either use the calculated value of the spring constant along with the local gravitational acceleration, or we can simply take advantage of the ratio. The ratio will be both easier and more accurate. So
X/0.39 cm = 115 kg/0.65 cm
X = 44.85 kg/0.65
X = 69 kg
The player masses 69 kg.</span>
