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nikitadnepr [17]
3 years ago
14

You are at a circus and you see a stunt man climb up 29.4 meters into a cannon. He gets fired horizontally out of the cannon wit

h a speed of 57.1 m/s. How long was stunt man in the air for?
Physics
1 answer:
klemol [59]3 years ago
8 0

Answer:

t = 2.44 s

Explanation:

Given that,

A stunt man climb up 29.4 meters into a cannon. He gets fired horizontally out of the cannon with a speed of 57.1 m/s.

We need to find the time for which was the stunt man in the air. Let it is t. It can be calculated using second equation of motion as follows :

s=ut+\dfrac{1}{2}gt^2

u is initial speed and it is 0

s=\dfrac{1}{2}gt^2\\\\t=\sqrt{\dfrac{2s}{g}} \\\\t=\sqrt{\dfrac{2\times 29.4}{9.8}} \\\\t=2.44\ s

So, the stunt man is in the air for 2.44 seconds.

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The speed of a moving bullet can be deter-
Bad White [126]

Answer:

<em>v = 381 m/s</em>

Explanation:

<u>Linear Speed</u>

The linear speed of the bullet is calculated by the formula:

\displaystyle v=\frac{x}{t}

Where:

x = Distance traveled

t = Time needed to travel x

We are given the distance the bullet travels x=61 cm = 0.61 m. We need to determine the time the bullet took to make the holes between the two disks.

The formula for the angular speed of a rotating object is:

\displaystyle \omega=\frac{\theta}{t}

Where θ is the angular displacement and t is the time. Solving for t:

\displaystyle t=\frac{\theta}{\omega}

The angular displacement is θ=14°. Converting to radians:

\theta=14*\pi/180=0.2443\ rad

The angular speed is w=1436 rev/min. Converting to rad/s:

\omega = 1436*2\pi/60=150.3776\ rad/s

Thus the time is:

\displaystyle t=\frac{0.2443\ rad}{150.3776\ rad/s}

t = 0.0016 s

Thus the speed of the bullet is:

\displaystyle v=\frac{0.61}{0.0016}

v = 381 m/s

7 0
3 years ago
Light incident upon a pane of glass slows down in passing through the glass, Does it emerge at a slower speed or at its initial
Simora [160]

Answer:

It will emerge at its initial speed not a slower speed.

Explanation:

It will emerge at the initial speed because the medium at the point of emergence is the same as the medium before incidence.

Light moves at a constant speed in any particular medium. Hence, the speed of light in air is constant in air and the speed of light in glass is constant in glass.

4 0
3 years ago
The electric field in a particular thundercloud is 3.8 x 105 N/C. What is the acceleration (in m/s2) of an electron in this fiel
Svetradugi [14.3K]

Answer:

Answer:

6.68 x 10^16 m/s^2

Explanation:

Electric field, E = 3.8 x 10^5 N/C

charge of electron, q = 1.6 x 10^-19 C

mass of electron, m = 9.1 x 10^-31 kg

Let a be the acceleration of the electron.

The force due to electric field on electron is

F = q E

where q be the charge of electron and E be the electric field

F = 1.6 x 10^-19 x 3.8 x 10^5

F = 6.08 x 10^-14 N

According to Newton's second law

Force  = mass x acceleration

6.08 x 10^-14 = 9.1 x 10^-31 x a

a = 6.68 x 10^16 m/s^2

Explanation:

8 0
3 years ago
Which statement about the positive and negative value of speed compared to velocity is true?
mestny [16]
D is the answer
Velocity maybe negative or positive
while speed is always positive
3 0
3 years ago
C is correct just an FYI
belka [17]

Answer:

Huh?

Explanation:

3 0
2 years ago
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