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nikitadnepr [17]
3 years ago
14

You are at a circus and you see a stunt man climb up 29.4 meters into a cannon. He gets fired horizontally out of the cannon wit

h a speed of 57.1 m/s. How long was stunt man in the air for?
Physics
1 answer:
klemol [59]3 years ago
8 0

Answer:

t = 2.44 s

Explanation:

Given that,

A stunt man climb up 29.4 meters into a cannon. He gets fired horizontally out of the cannon with a speed of 57.1 m/s.

We need to find the time for which was the stunt man in the air. Let it is t. It can be calculated using second equation of motion as follows :

s=ut+\dfrac{1}{2}gt^2

u is initial speed and it is 0

s=\dfrac{1}{2}gt^2\\\\t=\sqrt{\dfrac{2s}{g}} \\\\t=\sqrt{\dfrac{2\times 29.4}{9.8}} \\\\t=2.44\ s

So, the stunt man is in the air for 2.44 seconds.

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You apply a horizontal force of 25N to push a shopping cart across the parking lot at a constant velocity. a) what is the net fo
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(a) The net force on the shopping cart is zero.

(b) The the force of friction on the shopping cart is 25 N.

(c) When same force is applied to the shopping cart on a wet surface, it will move faster.

<h3>Net force on the shopping cart</h3>

The net force on the shopping cart is calculated as follows;

F(net) = F - Ff

where;

  • F is the applied force
  • Ff is the frictional force

ma = F - Ff

where;

  • a is acceleration of the cart
  • m is mass of the cart

at a constant velocity, a = 0

0 = F - Ff

F(net)  = 0

F = Ff = 25 N

Net force is zero, and frictional force is equal to applied force.

<h3>On wet surface</h3>

Coefficient of kinetic friction of solid surface is greater than that of wet surface.

Since frictional force limit motion, when the frictional force is smaller, the object tends to move faster.

Thus, the cart will move faster on a wet surface due to decrease in friction.

Learn more about frictional force here: brainly.com/question/24386803

#SPJ1

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