Answer:
t = 2.44 s
Explanation:
Given that,
A stunt man climb up 29.4 meters into a cannon. He gets fired horizontally out of the cannon with a speed of 57.1 m/s.
We need to find the time for which was the stunt man in the air. Let it is t. It can be calculated using second equation of motion as follows :
u is initial speed and it is 0
So, the stunt man is in the air for 2.44 seconds.
Answer:
Explanation:
The electric field produced by a single point charge is given by:
where
k is the Coulomb's constant
q is the charge
r is the distance from the charge
In this problem, we have
E = 1.0 N/C (magnitude of the electric field)
r = 1.0 m (distance from the charge)
Solving the equation for q, we find the charge:
Answer:
Explanation:
<u>Average Acceleration </u>
Acceleration is a physical magnitude defined as the change of velocity over time. When we have experimental data, we can compute it by calculating the slope of the line in velocity vs time graph.
Note: <em>We cannot see if the time axis is numbered in increments of 1 second, and we'll assume that. </em>
When , the graph shows a value of
When , the object is at rest,
We compute the average acceleration as
Answer:
Time = 80.91 seconds
Explanation:
Given the following data;
Velocity = 5.50 m/s.
Distance = 445 meters
To find the time;
Velocity can be defined as the rate of change in displacement (distance) with time. Velocity is a vector quantity and as such it has both magnitude and direction.
Mathematically, velocity is given by the equation;
Substituting into the formula, we have;
5.5 = 445/time
Time = 445/5.5
Time = 80.91 seconds