Question

You are at a circus and you see a stunt man climb up 29.4 meters into a cannon. He gets fired horizontally out of the cannon with a speed of 57.1 m/s. How long was stunt man in the air for?

Answer 1

Answer:

t = 2.44 s

Explanation:

Given that,

A stunt man climb up 29.4 meters into a cannon. He gets fired horizontally out of the cannon with a speed of 57.1 m/s.

We need to find the time for which was the stunt man in the air. Let it is t. It can be calculated using second equation of motion as follows :

$s=ut+\dfrac{1}{2}gt^2$

u is initial speed and it is 0

$s=\dfrac{1}{2}gt^2\\\\t=\sqrt{\dfrac{2s}{g}} \\\\t=\sqrt{\dfrac{2\times 29.4}{9.8}} \\\\t=2.44\ s$

So, the stunt man is in the air for 2.44 seconds.