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Rus_ich [418]
3 years ago
12

The record height of a man to date is 8 feet 11 inches​ (107 inches). If all men had identical body​ types, their weights would

vary directly as the cube of their heights. Assume that all men do have identical body types. If a man who is 5 feet 10 inches tall​ (70 inches) weighs 175175 ​pounds, approximately how much would a man with a height of 9 feet 2 inches9 feet 2 inches (110 inches )(110 inches) ​weigh? A man with a record height of 9 feet 2 inches9 feet 2 inches would weigh approximately nothing lbs.
Physics
1 answer:
Alisiya [41]3 years ago
5 0

Answer:

679.08 lbs

Explanation:

Here it is given that

m\propto h^3

m_1 = Mass of first person = 175 pounds

h_1 = Height of first person = 70 inches

m_2 = Mass of second person

h_2 = Height of second person = 110 inches

\frac{m_1}{m_2}=\frac{h_1^3}{h_2^3}\\\Rightarrow m_2=\frac{m_1h_2^3}{h_1^3}\\\Rightarrow m_2=\frac{175\times 110^3}{70^3}\\\Rightarrow m_2=679.08\ lb

The weight of the second person would be 679.08 lbs

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A lamp has a current of 2.17 A. In hours, how long does it take for 1 mole of electrons to pass through the lamp?
Gennadij [26K]

<u>Answer:</u> The amount of time needed for 1 mole of electrons to pass through the lamp is 12.33 hrs.

<u>Explanation:</u>

We are given:

Moles of electron = 1 mole

According to mole concept:

1 mole of an atom contains 6.022\times 10^{23} number of particles.

We know that:

Charge on 1 electron = 1.6\times 10^{-19}C

Charge on 1 mole of electrons = 1.6\times 10^{-19}\times 6.022\times 10^{23}=9.6352\times 10^4C

To calculate the time required, we use the equation:

I=\frac{q}{t}

where,

I = current passed = 2.17 A

q = total charge = 9.6352\times 10^4C

t = time required = ?

Putting values in above equation, we get:

2.17A=\frac{9.6352\times 10^4C}{t}\\\\t=\frac{9.6352\times 10^4C}{2.17A}=44402s

Converting this into hours, we use the conversion factor:

1 hr = 3600 seconds

So, 44402s\times \frac{1hr}{3600s}=12.33hr

Hence, the amount of time needed for 1 mole of electrons to pass through the lamp is 12.33 hrs.

3 0
3 years ago
A 2 kg blue car is moving 6 m/s to the right and collides with a 3 kg red car that is moving 2 m/s to the left. The cars collide
snow_lady [41]

Answer:

Their velocity after the collision is 1.2 m/s, to the right.

Explanation:

Given;

mass of the blue car, m₁ = 2 kg

initial velocity of the blue car, u₁ = 6 m/s

mass of the red car, m₂ = 3 kg

initial velocity of the red car, u₂ = 2 m/s

let the blue car moving to the right be in positive direction

also, let the red car moving to the left be in negative direction

Apply the principle of conservation of linear momentum for inelastic collision.

m₁u₁ - m₂u₂ = v(m₁ + m₂)

where;

v is their velocity after the collision

(2 x 6) - (3 x 2) = v(2 + 3)

12 - 6 = 5v

6 = 5v

v = 6/5

v = 1.2 m/s, to the right

Therefore, their velocity after the collision is 1.2 m/s, to the right.

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3 years ago
Complete the paragraph to describe the relationship between kinetic energy and braking distance. Use . A car moves at a speed of
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4 years ago
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A tourist being chased by an angry bear is running in a straight line toward his car at a speed of 4.2 m/s. The car is a distanc
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Explanation:

It is known that the relation between speed and distance is as follows.

               velocity = \frac{distance}{time}

As it is given that velocity is 6 m/s and distance traveled by the bear is (d + 29). Therefore, time taken by the bear is calculated as follows.

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Now, equation both equations (1) and (2) equal to each other we will calculate the value of d as follows.

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Thus, we can conclude that the maximum possible value for d is 67.66.

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