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olga nikolaevna [1]
3 years ago
9

Eight less than the quotient of a number and 3 is 18

Mathematics
1 answer:
Dmitriy789 [7]3 years ago
8 0
The answer is 39 
Hope this helps
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-3 (5-x) > -4x-7+10x​
Anastaziya [24]

Answer:

-8/3

Step-by-step explanation:

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3 years ago
Complete the comparison : 17>?
sveticcg [70]
Your ans is 1 
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4 0
2 years ago
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avanturin [10]

the only 2 possible answers are 2 and -2 .But the answer is y=2 because x is positive

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3 years ago
A coin is tossed 8 times. What is the probability of getting all heads? Express your answer as a simplified fraction or a decima
kumpel [21]

Answer:

The probability of getting all heads is \frac{1}{256}.

Step-by-step explanation:

For each time the coin is tossed, there are only two possible outcomes. Either it is heads, or it is not. So we use the binomial probability distribution to solve this problem.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

In this problem, we have that:

A coin is tossed 8 times. This means that n = 8

In each coin toss, heads or tails are equally as likely. So p = \frac{1}{2}

What is the probability of getting all heads?

This is P(X = 8)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

[tex]P(X = 8) = C_{8,8}*(\frac{1}{2})^{8}*(1 - \frac{1}{2})^{0} = \frac{1}{256}

The probability of getting all heads is \frac{1}{256}.

7 0
3 years ago
Round 15.186 the 1 is underlined.
taurus [48]
15.2 Is the answer...Hope this helps
4 0
3 years ago
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