Answer:
The absolute minimum value is "
" and the absolute maximum value is "
".
Step-by-step explanation:
Given:
![f(x)=x^2-x-5](https://tex.z-dn.net/?f=f%28x%29%3Dx%5E2-x-5)
on,
![[0,5]](https://tex.z-dn.net/?f=%5B0%2C5%5D)
By differentiating it, we get
⇒ ![f'(x)=2x-1](https://tex.z-dn.net/?f=f%27%28x%29%3D2x-1)
Set ![f'(x)=0](https://tex.z-dn.net/?f=f%27%28x%29%3D0)
then,
⇒ ![2x-1=0](https://tex.z-dn.net/?f=2x-1%3D0)
![2x=1](https://tex.z-dn.net/?f=2x%3D1)
(Critical point)
When x=0,
⇒ ![f(x)=-5](https://tex.z-dn.net/?f=f%28x%29%3D-5)
When
,
⇒
(Absolute minimum)
When ![x=5](https://tex.z-dn.net/?f=x%3D5)
⇒
(Absolute maximum)
Using the domain concept, the restrictions on the domain of (u.v)(x) are given by:
A. u(x) ≠ 0 and v(x) ≠ 2.
<h3>What is the domain of a data-set?</h3>
The domain of a data-set is the set that contains all possible input values for the data-set.
To calculate u(x) x v(x) = (u.v)(x), we calculate the values of u and v and then multiply them, hence the restrictions for each have to be considered, which means that statement A is correct.
Summarizing, u cannot be calculated at x = 0, v cannot be calculated at x = 2, hence uv cannot be calculated for either x = 0 and x = 2.
More can be learned about the domain of a data-set at brainly.com/question/24374080
#SPJ1
X=4. If k is the midpoint then JK is equal to KL. Since JK is 7 then KL is also 7 meaning JK is 14. JK is represented by the expression 4x-2 so you just set that expression equal to 14 and solve for x. Hope this helped!
Answer: 15
Step-by-step explanation: Use the formula: ![a^{2}+b^{2}=c^{2}](https://tex.z-dn.net/?f=a%5E%7B2%7D%2Bb%5E%7B2%7D%3Dc%5E%7B2%7D)
Remember
should always be the hypotenuse or the longest side.
---> evaluate the exponents
----> subtract 12544 to the other side
---> take the square root of both sides
![b=15](https://tex.z-dn.net/?f=b%3D15)
She didn't estimate her answer first
WHAT IS THE QUESTION ON KENDRA'S HOMEWORK?