What is the sales tax on a car stereo costing 399 if the tax rate is 5.5%

Help me with this question ASAP

makkiz [27]

11. D. $5.50

12. B. $21.35

5 0

3 years ago

HElp please i need help in question number 5????

likoan [24]

Answer:

g

Step-by-step explanation:

7 0

3 years ago

Water freezes at 0 degrees Celsius. A student discovered that adding half a cup of salt to a gallon of water lowers its freezing

Artemon [7]

Answer:

-7°C

Step-by-step explanation:

Freezing point of water = 0°C

By adding salt, freezing point lowers by 7°C ;

The freezing point of salt water can be expressed as ;

Since temperature lowers :

Freezing point of salt water :

Freezing point of water - 7°C

0°C - 7°C

= - 7°C

4 0

3 years ago

A random sample of 77 fields of corn has a mean yield of 26.226.2 bushels per acre and standard deviation of 2.322.32 bushels pe

PSYCHO15rus [73]

Answer:

Therefore the 95% confidence interval is (25,707.480 < E < 26,744.920)

Step-by-step explanation:

n = 77

mean u = 26,226.2 bushels per acre

standard deviation s = 2,322.32

let E = true mean

let A = test statistic

Find 95% Confidence Interval

so

let A = (u - E) * ( $\sqrt{n}$ / s) be the test statistic

we want P( average_l < A < average_u ) = 95%

look for lower 2.5% and the upper 97.5% Because I think this is a 2-tail test

average_l = -1.96 which corresponds to the 2.5%

average_u = 1.96

P( -1.96 < A < 1.96) = 95%

P( -1.96 < (u - E) * ( $\sqrt{n}$ / s) < 1.96) = 95%

Solve for the true mean E ok

E < u + 1.96* (s / $\sqrt{n}$ )

from -1.96 < (u - E) * ( $\sqrt{n}$ / s)

E < 26,226.2 + 1.96*( 2,322.32 / $\sqrt{77}$ )

E < 26,226.2 + 518.7197348105429466

upper bound is 26,744.9197

or

u - 1.96* (s / $\sqrt{n}$ ) < E

26,226.2 - 518.7197348105429466 < E

25,707.48026519 < E

lower bound is 25,707.48026519

Therefore the 95% confidence interval is (25,707.480 < E < 26,744.920)

7 0

3 years ago

You have a credit card with a balance of $754.43 at a 13.6% APR. You have $300.00 available each month to save or pay down your

pochemuha

<span>B(n) = A(1 + i)^n - (P/i)[(1 + i)^n - 1]

where B is the balance after n payments are made, i is the monthly interest rate, P is the monthly payment and A is the initial amount of loan.

We require B(n) = 0...i.e. balance of 0 after n months.

so, 0 = A(1 + i)^n - (P/i)[(1 + i)^n - 1]

Then, with some algebraic juggling we get:

n = -[log(1 - (Ai/P)]/log(1 + i)

Now, payment is at the beginning of the month, so A = $754.43 - $150 => $604.43

Also, i = (13.6/100)/12 => 0.136/12 per month

i.e. n = -[log(1 - (604.43)(0.136/12)/150)]/log(1 + 0.136/12)

so, n = 4.15 months...i.e. 4 payments + remainder

b) Now we have A = $754.43 - $300 = $454.43 so,

n = -[log(1 - (454.43)(0.136/12)/300)]/log(1 + 0.136/12)

so, n = 1.54 months...i.e. 1 payment + remainder
</span>

8 0

4 years ago