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Klio2033 [76]
3 years ago
7

What element has the noble gas electron configuration [Kr]5524d105p?

Chemistry
1 answer:
Digiron [165]3 years ago
3 0

Answer:

What is a noble gas electron configuration?

A noble gas electron configuration is a configuration that completes the Octet Rule of achieving 8 valence electrons.

Atoms always behave in ways to achieve stability and as you probably know, Noble Gases are the most stable. Their configuration, with a full valence electron shell (8 electrons, when you add both the S & P sublevels together, this is why it’s called the Octet), is therefore desirable. This means metals on the far left of the table will lose electrons to achieve this noble gas configuration and nonmetals on the right will gain electrons (generally speaking).

For example; take Argon. Its electron configuration is 1s^2 2s^2 2p^6 3s^2 3p^6, meaning it has 8 valence electrons. Then, take Chlorine. It has the electron configuration 1s^2 2s^2 2p^6 3s^2 3p^5, meaning it has 7 valence electrons so it’s a very unhappy camper. It typically gains an electron to achieve the 8 valence electrons Argon has (even using the same configuration of 1s^2 2s^2 2p^6 3s^2 3p^6) because it’s Mega jealous of Argon’ s stability. Side note: this is why chlorine typically has a -1 charge!

In summary, an atom achieving a “Noble Gas configuration” is the same as saying an atom fulfilling the Octet Rule. Both mean that there are 8 valence electrons (electrons in shell furthest from nucleus). This is a stable form many atoms seek to achieve (of course, what’s a good rule in chemistry if there aren’t exceptions!).

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Which two organ systems work together to provide cells with oxygen and to remove carbon
-BARSIC- [3]

Answer:

Lungs

Explanation: The two organ systems that work together to provide the cells with oxygen and remove carbon dixoide from the body are the lungs.

3 0
3 years ago
A sample of FeCl3 has a mass of 36.45.How many molecules would that be?
stira [4]

Answer: 1.35x 10²³ molecules FeCl3

Explanation: First find the number of moles for FeCl3 using its molar mass which is equal to 162.2 g FeCl3

Convert moles of FeCl3 to molecules by using the Avogadro's number.

8 0
3 years ago
Ammonia, NH3 is a common base with Kb of 1.8 X 10-5. For a solution of 0.150 M NH3:
Vesnalui [34]

The concentrations : 0.15 M

pH=11.21

<h3>Further explanation</h3>

The ionization of ammonia in water :

NH₃+H₂O⇒NH₄OH

NH₃+H₂O⇒NH₄⁺ + OH⁻

The concentrations of all species present in the solution = 0.15 M

Kb=1.8 x 10⁻⁵

M=0.15

\tt [OH^-]=\sqrt{Kb.M}\\\\(OH^-]=\sqrt{1.8\times 10^{-5}\times 0.15}\\\\(OH^-]=\sqrt{2.7\times 10^{-6}}=1.64\times 10^{-3}

\tt pOH=-log[OH^-]\\\\pOH=3-log~1.64=2.79\\\\pH=14-2.79=11.21

8 0
3 years ago
According to the law of conservation of energy, A) an object loses most of its energy as friction. Eliminate B) the total amount
Aloiza [94]

Answer:

B

Explanation:

This is what the law of conservation of energy is.

4 0
4 years ago
Calculate the standard molar enthalpy of formation for Na2O(s), given that the standard enthalpy of formation for Na2O2(s) is -5
Anarel [89]

Answer:

- 416 kJ/mol

Explanation:

The standard enthalpy of the reaction (Δ H ∘ rxn) is independent of the pathway, so it can be calculated by the enthalpy of formation of the reactants and the products:

Δ H ∘ rxn = ∑n*Δ H ∘f products - ∑n*Δ H ∘f reactants

Where n is the number of moles in the balanced reaction. So, for the reaction given:

Na₂O(s) + 1/2O₂(g) → Na₂O₂(s)

Because O₂ is formed by only one elements, its Δ H ∘f is 0 kJ/mol:

-89.0 = (1*(-505) - (1*Δ H ∘fNa₂O)

Δ H ∘fNa₂O = -505 + 89

Δ H ∘fNa₂O = - 416 kJ/mol

3 0
4 years ago
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