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3 years ago

How many Electrons make up 1 Proton

Chemistry

2 answers:

Nastasia [14]3 years ago

6 0

the answer is that you need 1836 electron to equal the mass of a proton.

meriva3 years ago

6 0

A proton has a mass of 1.0073. amu, a neutron 1.0087, and an electron 5.486 x-4 so it would take 1836 electrons to equal the mass of 1 proton.
hope that helps you

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Propane burns in oxygen to produce carbon dioxide and steam. The unbalanced equation for this reaction is: C3H8 + O2 → CO2 + H2O

NemiM [27]

Here is your answer

C3H8 + O2-----> CO2 + H2O

Balancing C atoms

C3H8 + O2------> 3CO2 + H2O

Balancing H atoms

C3H8 + O2------> 3CO2 + 4H2O

Balancing O atoms

C3H8 + $\bold{5}$ O2-------> $\bold{3}$ CO2 + $\bold{4}$ H2O

Hence the equation is balanced.

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kondaur [170]

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3 years ago

True or false I need help

mrs_skeptik [129]

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3 years ago

Read 2 more answers

An apparatus consists of a 4.0 dm^3 flask containing nitrogen gas at 25°c and 803 kPa, it is joined by a valve to a 10.0dm^3 fla

krok68 [10]

Answer:

so total pressure is = 261.92 kPa

partial pressure of Ar gas= 33.50 Kpa

partial pressure of N2 gas = 227 kPa

Explanation:

PV = nRT

n = PV / RT

as we know that 1dm3 = 1 Liter

smaller flask before mixing

ideal gas constant

n = (803 kPa) x (4L) / ((8.3144621 L kPa/K mol) x (25 + 273 K))

n = (3212 kPa L) / ((8.3144621 L kPa/K mol) x (298 K))

n = (3212 kPa L) /2477.7

n= 1.29 mol

In the larger flask:

n = (47.2 kPa) x (10 L) / ((8.3144621 L kPa/K mol) x (25 + 273 K)) =

n = (472 kpaL/ 2477.7

n= 0.19 mol

PV = nRT

P = nRT / V

After mixing:

P = (1.29 mol + 0.19 mol) x (8.3144621 L kPa/K mol) x (25+ 273 K) / (4 L + 10 L)

= (1.48) x (2477.7 / (14 L)

= 261.92 kPa total pressure

so total pressure is = 261.92 kPa

(261 kPa) x (0.19 mol Ar) / (1.29 + 0.19mol) =

= 49.59/1.48 = 33.50 Kpa for Arg

(261 kPa total) - (33.50 kPa Ar) = 227 kPa for N2

partial pressure of Ar gas= 33.50 Kpa

partial pressure of N2 gas = 227 kPa

3 0

3 years ago