Question

Solve the system of equations!!!!!!!!!

Answer 1

Answer:

(7, 220) and (-1, -20)   (x,y)

Step-by-step explanation:

put value of y in eq 2

30x + 10 = 5x² - 25

5x² - 25 - 30x -10 =0

5x² -30x -35 =0

x² -6x -7 =0  by dividing 5 on both sides

quadratic eq ax²+bx+c=0

a=1, b= -6, c -7

use quadratic formula to find value of x

x= (-b+-√b^2-4ac) / 2a

by putting values of a, b and c

x= (6 ± 8)/2

x= (6 + 8)/2  and x= (6 - 8)/2

x= 14/2=7            x= -2/2= -1

so, x= 7, -1

put values of x in eq 1

for x= 7

y= 30(7) + 10

y= 210 + 10

y= 220

now for x= -1

y= 30(-1) + 10

y= -30 + 10

y= -20