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3 years ago

HELP ME PLS THIS IS HARD

Mathematics

1 answer:

tensa zangetsu [6.8K]3 years ago

8 0

Answer:

the answer is C because both the x and y values are multiplied by 4. You cant dilate something by a scale factor of a negative number, so A can be crossed out. B and D only dilate one value of the dilation, so they are incorrect. So C is the only answer.

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A study was conducted to determine whether magnets were effective in treating pain. The values represent measurements of pain us

amm1812

Answer:

Given:

Sham: n= 20, x=0.44, s=1.24,

Magnet:n= 20, x =0.49, s= 0.95

For Sham:

Sample size, n = 20

Sample mean = 0.44

Standard deviation = 1.24

For Magnet:

Sample size = 20

Sample mean = 0.49

Standard deviation = 0.95

The null and alternative hypotheses:

H0: s1²=s2²

H1: s1² ≠ s2²

a) To find the test statistics, use the formula:

$\frac{s1^2}{s2^2}$

$\frac{1.24^2}{0.95^2} = \frac{1.5376}{0.9025} = 1.7037$

Test statistics = 1.7037

b) P-value:

Sham: degrees of freedom $= n - 1 = 20 - 1 = 19$

Magnet: degrees of freedom $= n - 1 = 20 - 1 = 19$

The critical values:

[Za/2, df1, df2)], [(1 - Za/2), df1, df2]

$f[0.05/2, 19, 19], f[(1 - 0.05/2), 19, 19]$

$f[0.025, 19, 19], f[0.975, 19, 19]$

$(2.526, 0.3958)$

The rejection region:

Reject H0, if F < 0.3958 or if F > 2.526

c) Conclusion:

Since the critical values of test statistic is between (0.3958 < 1.7037 < 2.526), we fail to reject null hypothesis H0.

There is insufficient evidence to to support the claim that those given a sham treatment have reductions that vary more than those treated with magnets

3 0

2 years ago

An investigator wants to assess whether the mean m = the weight of passengers flying on small planes exceeds the FAA guideline o

stira [4]

Answer:

$H_{0}: \mu= 185$ and $H_{a}: \mu > 185$

Step-by-step explanation:

The null hypothesis $H_{0}$ states that a population parameter (such as the mean, the standard deviation, and so on) is equal to a hypothesized value. We can write the null hypothesis in the form $H_{0}: parameter = value$

In this context, the investigator's null hypothesis should be that the average total weight is no different than the reported value by the FAA. We can write it in this form $H_{0}: \mu= 185$ .

The alternative hypothesis $H_{a}$ states that a population parameter is smaller, greater, or different than the hypothesized value in the null hypothesis. We can write the alternative hypothesis in one of three forms

$H_{a}: parameter > value\\H_{a}: parameter < value\\H_{a}: parameter \neq value$

The investigator wants to know if the average weight of passengers flying on small planes exceeds the FAA guideline of the average total weight of 185 pounds. He should use $H_{a}: \mu > 185$ as his alternative hypothesis.

7 0

3 years ago

Decide which chi-square test (goodness-of fit, homogeneity, or independence) would be most appropriate for the given situation.

sasho [114]

Answer:

C. Test for Goodness-of-fit.

Step-by-step explanation:

C. Test for Goodness-of-fit would be most appropriate for the given situation.

A. Test Of Homogeneity.

The value of q is large when the sample variances differ greatly and is zero when all variances are zero . Sample variances do not differ greatly in the given question.

B. Test for Independence.

The chi square is used to test the hypothesis about the independence of two variables each of which is classified into number of attributes. They are not classified into attributes.

C. Test for Goodness-of-fit.

The chi square test is applicable when the cell probabilities depend upon unknown parameters provided that the unknown parameters are replaced with their estimates and provided that one degree of freedom is deducted for each parameter estimated.

4 0

2 years ago

On Monday a company stock closed at a price of $30.80 per share. On Tuesday it increased by $1.20 per share. On Wednesday it fel

aleksley [76]

Tuesday:
30.80 + 1.20 = 32.00

Falling by 6.25% means it ends up being 93.75% of what it used to be (100% - 6.25% = 93.75%)

Wednesday:
32.00 * 0.9375 = 30

Thursday:
30 * 0.96 = 28.8

Friday:
28.8 * 1.025 = 29.52

Net change means you subtract to get the difference.

Net change = Final - initial
= 29.52 - 30.80
= -1.28

The stock fell $1.28

3 0

3 years ago

Read 2 more answers

What number is represented by these base ten blocks

MAXImum [283]

Answer:

Base ten blocks can represent values such as 1, 10, 100, and 1000.

4 0

3 years ago