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ss7ja [257]
3 years ago
13

The wholesale cost of a pair of sandals at a shoe store is $22.60. The markup for the sandals is 45%. What is the selling price

of the sandals?
Mathematics
1 answer:
uysha [10]3 years ago
8 0

Answer:

The selling price of sandals is: $32.77

Step-by-step explanation:

Mark up is the price that is added to the cost price of a product for profit.

Given

Price of sandals = $22.60

Mark up = 45%

To find the price with mark up, we will find the amount of mark up and then add it to the cost price of sandals.

Mark\ up = 45\%\ of\ 22.60\\= 0.45*22.60\\=10.17

The mark up is $10.17

Now,

Selling\ price = Cost + mark\ up\\= 22.60+10.17\\=32.77

Hence,

The selling price of sandals is: $32.77

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Answer:

a. 12 yd

Step-by-step explanation:

\sqrt{ {15}^{2} -  {9}^{2}  }  = 12

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3 years ago
Find the equation of all tangent lines having slope of -1 that are tangent to the curve y=(9)/(x+1)
fredd [130]

Answer:

f(x)=\frac9{x+1}\\ f'(x)=-\frac9{(x+1)^2}\\ f'(x)=-1\ \iff\ -\frac9{(x+1)^2}=-1\ \to \ \frac9{(x+1)^2}=1\ \to \ (x+1)^2=9\\ |x+1|=3\ \to \ x+1=3\ \vee\ x+1=-3\\ x_1=2\ \vee\ x_2=-4\\ f(x_1)=f(2)=\frac9{2+1}=3\\ f(x_2)=f(-4)=\frac9{-4+1}=-3

First tangent line:

y=f'(x_1)\cdot (x-x_1)+f(x_1)\ \to \ y=-1(x-2)+3\ \to \ y=-x+5

Second tangent line:

y=f'(x_2)\cdot (x-x_2)+f(x_2)\ \to \ y=-1(x+4)-3\ \to \ y=-x-7


Notice: slope of -1 means that both f'(x_1), \ f'(x_2) are equal to -1, so f'(x_1)=-1 \ and \ f'(x_2)=-1


6 0
3 years ago
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Given: △ABC, m∠A=60° m∠C=45°, AB=8 Find: Perimeter of △ABC, Area of △ABC
jarptica [38.1K]

We are given

△ABC, m∠A=60° m∠C=45°, AB=8

Firstly, we will find all angles and sides

Calculation of angle B:

we know that sum of all angles is 180

m∠A+ m∠B+m∠C=180

we can plug values

60°+ m∠B+45°=180

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we can use law of sines

\frac{AB}{sin(C)}=\frac{BC}{sin(A)}

now, we can plug values

\frac{8}{sin(45)}=\frac{BC}{sin(60)}

BC=\frac{8}{sin(45)} \times sin(60)

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Calculation of AC:

\frac{AB}{sin(C)}=\frac{AC}{sin(B)}

now, we can plug values

\frac{8}{sin(45)}=\frac{AC}{sin(75)}

AC=\frac{8}{sin(45)} \times sin(75)

AC=10.928

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p=AB+BC+AC

we can plug values

p=10.928+8+9.798

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Area:

we can use formula

A=\frac{1}{2}AB \times AC \times sin(A)

now, we can plug values

A=\frac{1}{2}8 \times 10.928 \times sin(60)

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