2 years ago

3 minus the product of a number and k

Mathematics

1 answer:

timofeeve [1]2 years ago

3 0

Answer:

let the number be n :

$3 \times n = k \\ { \underline{ \: \: 3n = k \: \: }}$

You might be interested in

Simplify. (w5) I need this ASAP please

Ilya [14]

I’m pretty sure it’s w^25

5 0

2 years ago

What is the value of x in the diagram below? 2 right triangles are stacked. The bottom triangle has a side length of 9 units and

ehidna [41]

Answer:

18 sqrt2/ sqrt3

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers

Which explains whether or not the values in the table represent a direct variation?

Assoli18 [71]

Answer:

This function represents a direct variation because it passes through the origin and has a constant rate

4 0

2 years ago

Order these numbers from least to greatest. 104/25 4.104 4 1/10 4.74

sammy [17]

I believe it would be 4 1/10 ,4.104, 104/25, 4.74

3 0

2 years ago

The fish population of Lake Collins is decreasing at a rate of 5% per year. In 2004 there were about 1,350 fish. Write an expone

ad-work [718]

Answer:

Part 1) The exponential function is equal to $y=1,350(0.95)^{x}$

Part 2) The population in 2010 was $992\ fish$

Step-by-step explanation:

Part 1) Write an exponential decay function that models this situation

we know that

In this problem we have a exponential function of the form

$y=a(b)^{x}$

where

y ----> the fish population of Lake Collins since 2004

x ----> the time in years

a is the initial value

b is the base

we have

$a=1,350\ fish$

$b=(100\%-5\%)=95\%=0.95$

substitute

$y=1,350(0.95)^{x}$ ----> exponential function that represent this scenario

Part 2) Find the population in 2010

we have

$y=1,350(0.95)^{x}$

For $x=(2010-2004)=6\ years$

substitute

$y=1,350(0.95)^{6}=992\ fish$

7 0

2 years ago