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3 years ago

In the picture below and show steps or explain

Mathematics

1 answer:

telo118 [61]3 years ago

3 0

An operation that is done to a value and it stays the same, it is called the "identity property".

Some quick examples:

Adding any number with zero will result in the same number.

Multiplying any number with one will result in the same number.

Hope this helps!

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Solve for y<br><br> .<br> =6y2<br> Simplify your answer as much as possible.

Scorpion4ik [409]

Y could be twelve, but I think I'm a 100% wrong. :'D

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4 years ago

What is the LCM of 5,13 and 10

RUDIKE [14]

Answer:

Step-by-step explanation:

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3 years ago

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Given that x is an even number, express, in terms of x, the product of the next two odd numbers.

wariber [46]

Answer:

Odd is the answer.

Step-by-step explanation:

An even number can be written in the form 2x, where x is an integer.

An odd number can be written in the form 2x + 1, where x is an integer.

So two odd numbers can be represented by 2a +1 and 2b +1, the product would be:

(2a + 1)(2b +1) = 4ab + 2a + 2b + 1 = which can be written as 2(2ab + a +b) + 1, but 2ab +a + b represents some integer, so 2ab + a + b = x.

So (2a + 1)(2b + 1) = 2(2ab + a + b ) + 1 = 2x +1 which is odd.

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2 years ago

Becky,Markus, and Hallie each earned $2.15 raking leaves.how much did they earn together?

Goshia [24]

Answer:

4.3

Step-by-step explanation:

2.15 times 2 is 4.3

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3 years ago

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A publisher reports that 75% of their readers own a particular make of car. A marketing executive wants to test the claim that t

Korolek [52]

Answer:

The p-value of the test is of 0.0536 > 0.02, which means that there is not sufficient evidence at the 0.02 level to support the executive's claim.

Step-by-step explanation:

A publisher reports that 75% of their readers own a particular make of car. A marketing executive wants to test the claim that the percentage is actually different from the reported percentage.

At the null hypothesis, we test if the proportion is of 75%, that is:

$H_0: p = 0.75$

At the alternate hypothesis, we test if the proportion is different of 75%, that is:

$H_1: p \neq 0.75$

The test statistic is:

$z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}$

In which X is the sample mean, $\mu$ is the value tested at the null hypothesis, $\sigma$ is the standard deviation and n is the size of the sample.

75% is tested at the null hypothesis:

This means that $\mu = 0.75, \sigma = \sqrt{0.75*0.25}$

A random sample of 280 found that 70% of the readers owned a particular make of car.

This means that $n = 280, X = 0.7$

Value of the test statistic:

$z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}$

$z = \frac{0.7 - 0.75}{\frac{\sqrt{0.75*0.25}}{\sqrt{280}}}$

$z = -1.93$

P-value of the test and decision:

The p-value of the test is the probability of finding a sample proportion differing from 0.75 by at least |0.7 - 0.75| = 0.05, which is P(|z| > 1.93), which is 2 multiplied by the p-value of z = -1.93.

Looking at the z-table, z = -1.93 has a p-value of 0.0268.

2*0.0268 = 0.0536.

The p-value of the test is of 0.0536 > 0.02, which means that there is not sufficient evidence at the 0.02 level to support the executive's claim.

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3 years ago