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kolbaska11 [484]

3 years ago

9

True or False; In spherical geometry, there is only one equilateral triangle.

1 answer:

Elodia [21]3 years ago

3 0

It's true. It must equal 180 degrees and the only way to accomplish that while it being an equilateral triangle is by having only one triangle! :)

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Please help with this....

Dima020 [189]

Answer:

i think its 20

Step-by-step explanation:

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3 years ago

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HELP PLEASE NO LINKS TELL ME WHAT OPTION

IgorLugansk [536]

Answer:

I think it is "The length of each shape will be an even number.

Step-by-step explanation:

"The square cuboid, square box, or right square prism (also ambiguously called square prism) is a special case of the cuboid in which at least two faces are squares."

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3 years ago

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Which correlation coefficient best matches the graph?

Ymorist [56]

Answer:

The correlation coefficient r measures the direction and strength of a linear relationship. Calculating r is pretty complex, so we usually rely on technology for the computations. We focus on understanding what r says about a scatterplot.❤

7 0

3 years ago

I don’t understand how to do this

schepotkina [342]

Answer:

The solution is $x =0.$

Step-by-step explanation:

The equation

$\bold{(1).}\: sin(\dfrac{3\pi }{2} +x)+sin(\dfrac{3\pi }{2} +x) =-2$

can be rewritten as

$2* sin(\dfrac{3\pi }{2} +2) =-2$

and can be further simplified to

$sin(\dfrac{3\pi }{2}+x ) =-1$ .

Now, taking the inverse sine of both sides we get:

$sin^{-1}(sin(\dfrac{3\pi }{2} +x) =sin^{-1}(-1)$

$\bold{(2).}\: \dfrac{3\pi }{2} +2 =sin^{-1}(-1)$

The value of the right side on the interval $[0,2\pi)$ is

$sin^{-1}(-1) = \dfrac{3\pi}{2} \: \:( \text{or }270^o)$ ,

which makes the equation (2)

$\dfrac{3\pi }{2}+x =\dfrac{3\pi}{2}$

solving for $x$ gives

$\boxed{x = 0}$

which is our solution.

4 0

3 years ago

According to data from the state blood program, 40 percent of all individuals have group A blood. If six individuals give blood,

Serjik [45]

Answer: 0.27648

Step-by-step explanation:

Given : The proportion of all individuals have group A blood : p=0.040

Total individuals give blood : n= 6

Let X be the number of individuals have group A blood.

Since all individual are independent of each other.

$X\sim Bin(n=6, p=0.40)$

Formula : $P(X=x)=^nC_xp^x(1-p)^{n-x}$ , where n= sample size , p = probability of getting success in each trial.

The probability that exactly three of the individuals have group A blood. :

$P(x=3)= ^6C_3(0.40)^3(1-0.4)^3\\\\= \dfrac{6!}{3!3!}\times(0.40)^3(0.60)^3\\\\=0.27648$

The probability that exactly three of the individuals have group A blood. is 0.27648

8 0

3 years ago