If the grams of acetic acid is given, we can use this to calculate for the mass percent acetic acid in the vinegar.
The formula is:
%acetic acid = (grams of acetic acid in vinegar)/ grams of vinegar x 100%
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Answer:
z = 18,46%
Explanation:
First we need to discover the mole number of the O2 produced so we use PV=nRT
734 torr * 57.2*10^-3 L = n 62.3637 * 295.15 K
n = 
n = 
n = 2,28 * 10^-3 mole
The reaction to the decomposition is:
2 NaClO3 --> 2 NaCl + 3 O2
2 mole NaClO3 - 3 moles O2
x - 2,28*10^-3 moles O2
X= 1,52*10^-3 moles of NaClO3
1 moles of NaClO3 - 106,44 g
1,52*10^-3 moles of NaClO3 - y
y = 0,1617 g
0,8765 g - 100%
0,1617 g - z
z = 18,46%
Hey there !
Answer BChemical properties are
characteristic behaviors of a substance when it is found in the presence of
another substance. To investigate chemical properties we will have to carry out
chemical transformations (performing chemical tests) and it is generally not
possible to recover the sample used (because it suffers changes giving rise to
other substances).
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