Answer:
If you call the smaller integer "x" and the greater integer "y", then:
x+y=3x-11 The sum of the two is 11 less than 3 times the smaller
y=x+1 Because they are consecutive, the greater must be 1 more than the smaller
Then you can solve for x:
x+(x+1)=3x-11 Substitute x+1 for y
2x+1=3x-11 Combine like terms
2x+12=3x Add 11 to both sides
12=x Subtract 2x from both sides
The smaller integer is 12, thus the greater integer is 1 more or 13.
Check:
12+13=3(12)-11
25=36-11
25=25 Yes, so the integers are 12 and 13
Step-by-step explanation:
thats pretty much it
Answer:
2) (12 ÷ 3) +5
3) .483
Step-by-step explanation:
Answer:
y = 2x - 5
Step-by-step explanation:
y = 2x + b
-1 = 2(2) + b
-1 = 4 + b
-5 = b
Answer:
1/54
Step-by-step explanation:
I believe you would take the chance of just getting the brother(1/6) and times that by the chance of getting the sister(1/9) which would be 1/54.
Answer: B
Step-by-step explanation:
