Answer:
Reagent O₂ will be consumed first.
Explanation:
The balanced reaction between O₂ and C₄H₁₀ is:
2 C₄H₁₀ + 13 O₂ → 8 CO₂ + 10 H₂O
Then, by reaction stoichiometry, the following amounts of reactants and products participate in the reaction:
- C₄H₁₀: 2 moles
- O₂: 13 moles
- CO₂: 8 moles
- H₂O: 10 moles
Being:
- C: 12 g/mole
- H: 1 g/mole
- O: 16 g/mole
The molar mass of the compounds that participate in the reaction is:
- C₄H₁₀: 4*12 g/mole + 10*1 g/mole= 58 g/mole
- O₂: 2*16 g/mole= 32 g/mole
- CO₂: 12 g/mole + 2*16 g/mole= 44 g/mole
- H₂O: 2*1 g/mole + 16 g/mole= 18 g/mole
Then, by reaction stoichiometry, the following mass quantities of reactants and products participate in the reaction:
- C₄H₁₀: 2 moles* 58 g/mole= 116 g
- O₂: 13 moles* 32 g/mole= 416 g
- CO₂: 8 moles* 44 g/mole= 352 g
- H₂O: 10 moles* 18 g/mole= 180 g
If 78.1 g of O₂ react, it is possible to apply the following rule of three: if by stoichiometry 416 g of O₂ react with 116 g of C₄H₁₀, 62.4 g of C₄H₁₀ with how much mass of O₂ do they react?

mass of O₂= 223.78 grams
But 21.78 grams of O₂ are not available, 78.1 grams are available. Since you have less mass than you need to react with 62.4 g of C₄H₁₀, <u><em>reagent O₂ will be consumed first.</em></u>
Lithium oxide is able to undergo both the processes of dissolution and dissociation.
Dissociation refers to the break down a chemical substance into its constituents. Ionization refers to the loss of electrons from a chemical specie while dissolving refers to the ability of a solid to form a solution.
Let us now look at each of the following species;
- Lithium oxide undergoes dissolution and dissociation.
- Magnesium nitride undergoes dissolution and dissociation.
- Hydrobromic acid undergoes dissolution and dissociation.
Learn more about ionization: brainly.com/question/1602374
The number of particles= 1.43 x 10²⁴ particles
<h3>Further explanation</h3>
Given
53.2 L volume of gas at STP
Required
The number of particles
Solution
Conditions at T 0 ° C and P 1 atm are stated by STP (Standard Temperature and Pressure). At STP, Vm is 22.4 liters/mol.
So mol for 53.2 L :
= 53.2/22.4
= 2.375 moles
1 mol = 6.02 x 10²³ particles (molecules, atoms, ions)
The number of paricles for 2.375 moles gas :
= 2.375 x 6.02 x 10²³
= 1.43 x 10²⁴ particles