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3 years ago

What do you think are the necessary skills needed by scientists to solve a particular problem?

Chemistry

1 answer:

neonofarm [45]3 years ago

8 0

Answer:

The skills required to solve problems are known as analytical skills. You use analytical skills when detecting patterns, brainstorming, observing, interpreting data, integrating new information, theorizing, and making decisions based on the multiple factors and options available.

Explanation:

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A 50.0 mL sample of waste process water from a food processing plant weighing 50.1 g was placed in a properly prepared crucible

RideAnS [48]

Answer:

TS (total solid, mg/L) = 57,174 mg/L

VS (volatile solid, mg/L) = 24,088 mg/L

Explanation:

First step to solve this problem is to know data and questions:

Data:

Sample volume = 50 mL

Sample weight = 50.1 g

P1 (weight empty crucible) = 17.1234 g

P2 (weight after drying a 103º in oven) = 19.9821 g

P3 (weight after incinatrion 550º) = 18.7777 g

Questions:

TS = ?

VS = ?

Formula:

We need to use formulas to calculate total solid (TS) and volatile solid (VS), these are:

$TS =\frac{(P2-P1)*\frac{1,000 mg}{1g} }{Sample volumen (L)}$

$VS = \frac{(P2-P3)*\frac{1,000 mg}{1g} }{Sample volume (L)}$

We have to transform mL to L so we will divide mL by 1,000 the sample volume:

$Sample Volumen (L) = 50 mL * \frac{1L}{1,000 mL} = 0.05 L$

In the formula the value of 1,000 results by the convertion factor to transform grams to miligrams (we have to multiplie by 1,000)

Now we need to replace data on previous formulas and we will get TS and VS expressed in mg/L:

$TS = \frac{(19.9821 g-17.1234g)*\frac{1,000 mg}{1g} }{0.05L} = 57,174mg/L$

$VS = \frac{(19.9821g-18.7777g)*\frac{1,000mg}{1g} }{0.05L}=24,088 mg/L$

We divide TS and VS formula by sample volume because the exercise is asking us to express the results in mg/L.

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3 years ago

What would the [OH-] of a solution that has a pOH of 2.7 be?

Brilliant_brown [7]

Answer:

The [OH⁻] of a solution that has a pOH of 2.7 will be 2*10⁻³

Explanation:

The pOH (or potential OH) is a measure of the basicity or alkalinity of a solution.

pOH indicates the concentration of hydroxyl ions [OH-] present in a solution. In this way, pOH is defined as the negative logarithm of the activity of hydroxide ions, that is, the concentration of OH- ions:

pOH= -log [OH⁻]

In this case, pOH has a value of 2.7. Replacing:

2.7= -log [OH⁻]

and solving:

[OH⁻]=10⁻² ⁷

you get:

[OH⁻]≅ 2*10⁻³

The [OH⁻] of a solution that has a pOH of 2.7 will be 2*10⁻³

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3 years ago

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1016)(2.2 × 1010) = A × 10B A= B= Chemistry.

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