Answer: if doing it on ck-12 the answer is 40.1
Explanation:
<u>Given:</u>
Mass of Ag = 1.67 g
Mass of Cl = 2.21 g
Heat evolved = 1.96 kJ
<u>To determine:</u>
The enthalpy of formation of AgCl(s)
<u>Explanation:</u>
The reaction is:
2Ag(s) + Cl2(g) → 2AgCl(s)
Calculate the moles of Ag and Cl from the given masses
Atomic mass of Ag = 108 g/mol
# moles of Ag = 1.67/108 = 0.0155 moles
Atomic mass of Cl = 35 g/mol
# moles of Cl = 2.21/35 = 0.0631 moles
Since moles of Ag << moles of Cl, silver is the limiting reagent.
Based on reaction stoichiometry: # moles of AgCl formed = 0.0155 moles
Enthalpy of formation of AgCl = 1.96 kJ/0.0155 moles = 126.5 kJ/mol
Ans: Formation enthalpy = 126.5 kJ/mol
Your answer is option b
i.e. Red
because refractive index of red is more as compared to green, yellow and violet...
<h3><u>Answer;</u></h3>
= 5.1 g/L
<h3><u>
Explanation;</u></h3>
Using the equation;
PV = nRT , where P is the pressure,. V is the volume, n is the number of moles and T is the temperature and R is the gas constant, 0.08206 L. atm. mol−1.
Number of moles is 1 since one mole has a mass equivalent to the molar mass.
Therefore; We can find the volume and thus get the density.
<em>V = nRT/P</em>
<em> = (1 × 0.08206 × 237)/3.510</em>
<em> = 5.5408 L</em>
<em>Hence; Density = mass/volume </em>
<em> = 28.26 g/5.5408 L</em>
<em> = 5.1 g/L</em>
<em>The Density is 5.1 g/L or 0.005 g/cm³</em>
Answer:
No.
Explanation:
The balanced equation is,
2HCl + Na2S -> H2S + <u>2</u>NaCl
