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Na 2Co3
1*23=23. 2*12=24. 6*16=96
23+24+96=143
(23*100)/143. (24*100)/143. (96*100)/143
=16%. =16.7%. =67.1%
Answer:
The concentration of HI present at equilibrium is 0.471 M.
Explanation:
Answer:
C
Explanation:
If you move the decimal to the left it transforms the expression into scientific notation.
