The answer I’m guessing could be 7225000
Answer: 11 possible outcomes
This is all the possible outcomes
1,5 2,5 3,5 4,5 5,5 6,5 5,1 5,2 5,3 5,4 5,6
The amount of at least one dice having a 5 is 11
Use formula 2(n) - 1
2(6) - 1 = 11
Hope this helps ^_^
9^6 is that number in exponential form.
First square and add the both terms one by one
You get
then multiply them to get( - 2rs)
<span>measure of ∠EGF = 1/2( 180 - 50)
= 1/2(130)
= 65
</span><span>the measure of ∠CGF = 180 - 65
= 115</span>