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sleet_krkn [62]
3 years ago
6

Solve for the value of c. (2C+8) - (6c-6) ES O San 46

Mathematics
1 answer:
user100 [1]3 years ago
6 0
2c+8=0
2c=-8
2/2 -8/2
C=-4
Im not exactly sure what the ES O San and 46 is tho
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The rectangle below has an area of 81-x^2 square meters and a width of 9-x meters. What expression represents the length of the
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For this case we have that by definition, the area of a rectangle is given by:

A = w * l

Where:

w: Is the width of the rectangle

l: is the length of the rectangle

According to the data of the statement we have:

A = 81-x ^ 2\\w = 9-x

So, the length is given by:

l = \frac {A} {w}\\l = \frac {81-x ^ 2} {9-x}

We factor the numerator:

l = \frac {(9 + x) (9-x)} {9-x}

We simplify:

l = 9 + x

So, the length is 9 + x

Answer:

9 + x

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Answer:

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Step-by-step explanation:

(50km/h)(1.5h) =<em> 75km</em>

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How many gallons of a 80% antifreeze solution must be mixed with 80 gallons of 15% antifreeze to get a mixture that is 70% antif
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440 gallons of 80 % antifreeze solution must be mixed with 80 gallons of 15% antifreeze to get a mixture that is 70% antifreeze

<em><u>Solution:</u></em>

Let "x" be the gallons of 80 % antifreeze added

Therefore, "x" gallons of 80 % antifreeze solution must be mixed with 80 gallons of 15% antifreeze

Final mixture is x + 80

Therefore, we can frame a equation as:

"x" gallons of 80 % antifreeze solution must be mixed with 80 gallons of 15% antifreeze to get (x + 80) gallons of 70 % antifreeze

Thus, we get,

x gallons of 80 % + 80 gallons of 15 % = (x + 80) gallons of 70 %

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Thus 440 gallons of 80 % antifreeze solution must be mixed

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