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vredina [299]
3 years ago
13

Help me with this one pls

Mathematics
2 answers:
larisa [96]3 years ago
5 0

Answer:

C) 9x^2+24x+16

Step-by-step explanation:

\left(3x+4\right)^2

<u>Use Perfect Square Formula :</u>

<u />\left(a+b\right)^2=a^2+2ab+b^2

\left(3x\right)^2+2\cdot \:3x\cdot \:4+4^2

9x^2+24x+16

<u>OAmalOHopeO</u>

Effectus [21]3 years ago
4 0
Expand it, so you will get 9x^2 + 24x + 16
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Step-by-step explanation:

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Discrete Random variable:

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3 0
3 years ago
Read 2 more answers
In Image:
iris [78.8K]

Answer:

The answer to your question is          x ≠ -10   x ≠ 2     x ≠ -2

Solution                                                \frac{(x- 8)(x + 2)}{(x + 8)(x - 2)}      

Step-by-step explanation:

Process

1.- Factor all the polynomials

              \frac{x^{2} -3x - 40}{x^{2} + 8x - 20} / \frac{x^{2}+ 13x + 40}{x^{2}+ 12x + 20} = \frac{(x-8)(x + 5)}{(x + 10)(x- 2)} / \frac{(x+ 8)(x + 5)}{(x + 10)(x + 2)}

2.- Invert the second term

                                             = \frac{(x- 8)(x + 5)}{(x +10)(x - 2)}  \frac{(x+ 10)(x + 2)}{(x + 8)(x +5)}

3.- Simplify

                                              = \frac{(x- 8)(x + 2)}{(x + 8)(x - 2)}

4.- x must be different to

            x ≠ -10   x ≠ 2     x ≠ -2

This values are from the factor expressions and then equal to zero.

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