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vredina [299]
3 years ago
13

Help me with this one pls

Mathematics
2 answers:
larisa [96]3 years ago
5 0

Answer:

C) 9x^2+24x+16

Step-by-step explanation:

\left(3x+4\right)^2

<u>Use Perfect Square Formula :</u>

<u />\left(a+b\right)^2=a^2+2ab+b^2

\left(3x\right)^2+2\cdot \:3x\cdot \:4+4^2

9x^2+24x+16

<u>OAmalOHopeO</u>

Effectus [21]3 years ago
4 0
Expand it, so you will get 9x^2 + 24x + 16
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Answer:

D-70

Step-by-step explanation:

It is a combination C(8,4)

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Step-by-step explanation:

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3 years ago
Convert the Cartesian equation (x 2 + y 2)2 = 4(x 2 - y 2) to a polar equation.
SashulF [63]

<u>ANSWER</u>

{r}^{2}  = 4  \cos2\theta

<u>EXPLANATION</u>

The Cartesian equation is

{( {x}^{2}  +  {y}^{2} )}^{2}  = 4( {x}^{2} -  {y}^{2}  )

We substitute

x = r \cos( \theta)

y = r \sin( \theta)

and

{x}^{2}  +  {y}^{2}  =  {r}^{2}

This implies that

{( {r}^{2} )}^{2}  = 4(( { r \cos\theta)  }^{2} -  {(r \sin\theta) }^{2}  )

Let us evaluate the exponents to get:

{r}^{4}  = 4({  {r}^{2} \cos^{2}\theta } -   {r}^{2}  \sin^{2}\theta)

Factor the RHS to get:

{r}^{4}  = 4{r}^{2} ({   \cos^{2}\theta } -   \sin^{2}\theta)

Divide through by r²

{r}^{2}  = 4 ({   \cos^{2}\theta } -   \sin^{2}\theta)

Apply the double angle identity

\cos^{2}\theta -\sin^{2}\theta=  \cos(2 \theta)

The polar equation then becomes:

{r}^{2}  = 4  \cos2\theta

7 0
3 years ago
What is the simplest form of square root 1,764
oee [108]

\bf \sqrt{1764}~~ \begin{cases} 1764=&2\cdot 2\cdot 3\cdot 3\cdot 7\cdot 7\\ &2^2\cdot 3^2\cdot 7^2\\ &(2\cdot 3\cdot 7)^2\\ &42^2 \end{cases}\implies \sqrt{42^2}\implies 42

3 0
3 years ago
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