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guajiro [1.7K]
3 years ago
7

Circle the value that solutions of the inequality 2x - 3 < -9

Mathematics
1 answer:
velikii [3]3 years ago
5 0

Answer:

x < -3

Step-by-step explanation:

2x - 3 < -9

Add 3 to each side

2x - 3+3 < -9+3

2x < -6

Divide by 2

2x/2 < -6/2

x < -3

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Let [v1,v2,v3] be a set of nonzero vectors in r^m such that the (transpose of vi)*vj = 0 when i is not equal to j. show that the
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