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leonid [27]
3 years ago
15

Solve the literal equation for x: g= 4x+5xy

Mathematics
1 answer:
Andreas93 [3]3 years ago
3 0

The literal equation for x is \frac{g}{4+5y} given that g= 4x+5xy

The subject of a formula is a way of representing a variable in terms of other variables.

Given the equation

g= 4x+5xy

Factor out the common variable x

g= x(4+5y)

Divide both sides by 4+5y

\frac{g}{4+5y} =\frac{x(4+5y)}{4+5y} \\\frac{g}{4+5y} = x\\Swap\\x = \frac{g}{4+5y}

This shows that the literal equation for x is \frac{g}{4+5y}

Learn more here: brainly.com/question/21140562

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Susie scored 85, 84,and 78 on three of the four math tests. if her average score for the four tests was 86. what was her score o
nata0808 [166]
(85 + 84 + 78 + x) / 4 = 86
(247 + x) / 4 = 86
247 + x = 86 * 4
247 + x = 344
x = 344 - 247
x = 97 <=== her score was 97
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3 years ago
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(x+2)(x2 - 2x+4)expand and simplify​
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Answer:

Step-by-step explanation:

2x2 is 4

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Write 4 with denominator 5
valkas [14]

Answer:

4/5

Step-by-step explanation:

I'm not exactly sure what this question is asking but I'm guessing it's asking to create a fraction with the numerator as 4 and denominator as 5.

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3 years ago
The total number of​ restaurant-purchased meals that the average person will eat in a​ restaurant, in a​ car, or at home in a ye
zloy xaker [14]

Answer:

Number of​ restaurant-purchased meals eaten in a​ restaurant = 70

Number of​ restaurant-purchased meals eaten in a​ car = 22

Number of​ restaurant-purchased meals eaten in a​ home = 60

Step-by-step explanation:

Let the number of people that will eat in a restaurant be R.

Let the number of people that will eat in a car be C.

Let the number of people that will eat in a home be H.

From the information given in the problem we have,

R+C+H = 152 ____equation (1)

C+H-R = 12 ____equation (2)

R = H+10 ____equation (3)

1) Plugging in R=H+10 from equation 3 into the equation 2, we get

C+H-R=12

=> C+H-(H+10)=12

=> C+H-H-10=12

2) Cancelling out +H and -H, we get

C-10=12

3) Add 10 to both sides

C-10+10=12+10

4) Cancelling out -10 and +10, we get

C=22

5) Plugin C=22 in equation 1, we have

R+C+H = 152

=> R+22+H=152

Subtract 22 from both sides,

R+22+H-22=152-22

Cancelling out +22 and -22 from the left side, we get

R+H=130 ____let it be equation (4)

6) Plugin C=22 in equation 2, we have

C+H-R = 12

22+H-R = 12

Subtracting 22 from both the sides, we get

22+H-R-22 = 12-22

Cancelling out +22 and -22 from the left side,

H-R = -10 ____let it be equation (5)

7) Adding equation 4 and equation 5, we get

(R+H)+(H-R) = 130 + (-10)

=> R+H+H-R = 130-10

8) Cancelling out R and -R from the left side, we get

2H = 120

9) Dividing both sides by 2, we get

\frac{2H}{2} = \frac{120}{2}

10) Cancelling out the 2's from the left side, we have

H=60

11) Plugging in C=22 and H=60 in the equation 1, we have

R+C+H = 152

=> R+22+60=152

=> R + 82 = 152

12) Subtracting 82 from both the sides, we get

R + 82 -82 = 152 -82

13) Cancelling out +82 and -82 from the left side, we get

R = 70

<em>So, C=22, H=60, R=70</em>

8 0
3 years ago
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OleMash [197]
20-3h=2=>3h=20-2=18=>h=18/3=6
5 0
3 years ago
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