Question

2c2h2(l) 5o2(g) yeild 4co2(g) 2h2o(g) if the acetylene tank contains 37.0 mol of c2h2 and the oxygen tank contains 81.0 mol of o2, what is the limiting reactant for this reaction?

Answer 1

2C2H2(l)  +5O2(g)→ 4Co2(g)  + 2H2O

The   limiting  reactant  for reaction above is O2

explanation

 The limiting reagent is determined using mole ratio  of both reactant.

 that  is the  mole ratio  of  C2H2:O2  which is  2:5 .

 The mole ratio above  implies  that 37.0 mole  of C2H2   needs  37.0 moles  x5/2=92  moles of  O2.

Since the available moles of O2  was 81.0 mole  and 92  moles  are  required to completely  react with  C2H2 , O2   is  the limiting reagent.