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1 year ago

[?] describes how small molecules can be selectively removed from a colloidal suspension while retaining large molecules.

Chemistry

2 answers:

IceJOKER [234]1 year ago

7 0

Dialysis is correct……………

MaRussiya [10]1 year ago

7 0

Answer:

using a centrifuge

Explanation:

Centrifugation will make the large molecules to settle at the bottom.

The Most suitable answer is tyndall effect

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The decomposition of copper(II) nitrate on heating is endothermic reaction. 2Cu(NO3)2(s) → 2C10(s) + 4NO2(g) + O2(g) Calculate t

Basile [38]

Answer:

The enthalpy change for the given reaction is 424 kJ.

Explanation:

$2Cu(NO_3)_2(s)\rightarrow 2CuO(s) + 4NO_2(g) + O_2(g),\Delta H_{rxn}=?$

We have :

Enthalpy changes of formation of following s:

$\Delta H_{f,Cu(NO_3)_2}=-302.9 kJ/mol$

$\Delta H_{f,CuO}=-157.3 kJ/mol$

$\Delta H_{f,NO_2}= 33.2 kJ/mol$

$\Delta H_{f,O_2}= 0 kJ/mol$ (standard state)

$\Delta H_{rxn}=\sum [\Delta H_f(product)]-\sum [\Delta H_f(reactant)]$

The equation for the enthalpy change of the given reaction is:

$\Delta H_{rxn}$ =

$=(2 mol\times \Delta H_{f,CuO}+4\times \Delta H_{f,NO_2}+1 mol\times \Delta H_{f,O_2})-(2mol\times \Delta H_{f,Cu(NO_3)_2})$

$\Delta H_{rxn}$ =

$(2mol\times (-157.3 kJ/mol)+4\times 33.2 kJ/mol=1 mol\times 0 kJ/mol)-(2 mol\times (-302.9 kJ/mol)$

$\Delta H_{rxn}=424 kJ$

The enthalpy change for the given reaction is 424 kJ.

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4 years ago

Carbon dioxide is treated with coke.

Troyanec [42]

It reacts with it and creates carbon monoxide and the affects of it weakens

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3 years ago

Which sentence best describes the relationship between chlorophyll and the chloroplast?

Viktor [21]

Answer:

chlorophyll is a chemical found in a chloroplast

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4 years ago

What do all four of these types of molecules have in common?

nalin [4]

D. They all contain carbon as an important part of their structure.

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3 years ago

The conversion of acetyl chloride to methyl acetate occurs via the following two-step mechanism: Reaction sequence of acetyl chl

Svetlanka [38]

If the concentration of acetyl chloride is increased ten times the rate of reaction is increased ten times.

The conversion of acetyl chloride to methyl acetate is a substitution reaction. Recall that a substitution reaction is one in which a moiety in a molecule is replaced by another.

In this reaction, the CH3O- ion replaces the chloride ion. In the first step, the CH3O- ion attacks the substrate in a slow step. This creates a tetrahedral intermediate. Loss of the chloride ion yields the methyl acetate product.

The rate determining step is the formation of the tetrahedral intermediate. Since the reaction is first order in the acetyl chloride, if its concentration is increased ten times the rate of reaction is increased ten times.

Learn more: brainly.com/question/5624100

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3 years ago