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3 years ago

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Chemistry

1 answer:

Leto [7]3 years ago

8 0

Explanation:

Each sample has the same number of molecules.

simple

1 mole of oxygen have no. of molecules 1×6.022×10^23

and one mole of nitrogen have 1×6.62×10^23 molecules

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URGENT!!!

miv72 [106K]

<h3>Answer;</h3>

= 13.629 g of ZnCl2

<h3><u>Explanation;</u></h3>

The equation for the reaction.

Zn(s)+2HCL(aq)=>ZnCl2(aq)+H2(g)

Number of moles of Zinc;

Moles = mass/RAM

= 6.5 g/65g/mol

= 0.1 moles

The mole ration of Zn : ZnCl2 is 1 : 1

Therefore, number of moles of ZnCl2 is 0.1 moles

Mass = moles × Molar mass

= 0.1 ×136.286 g/mol

<u> = 13.629 g</u>

7 0

3 years ago

Help me get this right no links

Kisachek [45]

Answer:

The moons gravitational pull on Earth

6 0

3 years ago

How many grams of sodium acetate ( molar mass = 83.06 g/mol ) must be added to 1.00 Liter of a 0.200 M acetic acid solution to m

Pie

<u>Answer:</u> The mass of sodium acetate that must be added is 30.23 grams

<u>Explanation:</u>

To calculate the number of moles for given molarity, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}$

Molarity of acetic acid solution = 0.200 M

Volume of solution = 1 L

Putting values in above equation, we get:

$0.200M=\frac{\text{Moles of acetic acid}}{1L}\\\\\text{Moles of acetic acid}=(0.200mol/L\times 1L)=0.200mol$

To calculate the pH of acidic buffer, we use the equation given by Henderson Hasselbalch:

$pH=pK_a+\log(\frac{[\text{salt}]}{[\text{acid}]})$

$pH=pK_a+\log(\frac{[CH_3COONa]}{[CH_3COOH]})$

We are given:

$pK_a$ = negative logarithm of acid dissociation constant of acetic acid = 4.74

$[CH_3COONa]=?mol$

$[CH_3COOH]=0.200mol$

pH = 5.00

Putting values in above equation, we get:

$5=4.74+\log(\frac{[CH_3COONa]}{0.200})$

$[CH_3COONa]=0.364mol$

To calculate the mass of sodium acetate for given number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Molar mass of sodium acetate = 83.06 g/mol

Moles of sodium acetate = 0.364 moles

Putting values in above equation, we get:

$0.364mol=\frac{\text{Mass of sodium acetate}}{83.06g/mol}\\\\\text{Mass of sodium acetate}=(0.364mol\times 83.06g/mol)=30.23g$

Hence, the mass of sodium acetate that must be added is 30.23 grams

7 0

3 years ago

So I asked this question before but I messed it up so basically my best friend has a bf and her bf keeps messing with other girl

OleMash [197]

yeah, let her b0yfriend know what she told you and you are telling him that simply because you want to avoid problems between them.

4 0

3 years ago

How many mono-; di- ; and trichloro derivatives are possible for cyclopentane?

Studentka2010 [4]

Mono - 1 Di- 2 Tri - 4

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4 years ago