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maria [59]
2 years ago
13

33/23 rounded to the nearest tenth

Mathematics
1 answer:
marysya [2.9K]2 years ago
7 0
1.4347826

Find the number in the tenth place 4
and look one place to the right for the rounding digit 3. Round up if this number is greater than or equal to 5 and round down if it is less than 5.
Answer- 1.4
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Help me pleasee<br> Questions r in picture
jok3333 [9.3K]
<h2>Answer:</h2>

\large \bf\implies\frac{12}{61}

<h2>Step-by-step explanation:</h2>

<h2>Given :</h2>

\tt \frac{8}{101} , \frac{9}{91} , \frac{10}{81} , \frac{11}{71} ...

<h2>To Find :</h2>

  • nth term

<h2>Solution :</h2>

We have to add 1 in numerator and -10 in denominator because

\tt \frac{8}{101} , \frac{9}{91} , \frac{10}{81} , \frac{11}{71} ...[Given]

\frac{8  \: + \:  1}{101 \:  - \:  10}  =  \frac{9}{91} \\\\  \frac{9 + 1}{91 - 10}  =  \frac{10}{81}  \\ \\ \frac{10 + 1}{81 - 10}  =  \frac{11}{71}  \\ \\ \frac{11 + 1}{71 - 10}  =  \frac{12}{61} ...

The difference is 1 in numerator so we add 1 and the difference is -10 in denominator so we subtract -10.

4 0
2 years ago
Each of the students im Romi's class raised at least $25 during the jump-a-thon. What is the least amount of money the class rai
EastWind [94]
If each of the 28 students made at least $25, you would multiply 28 and 25 together to obtain the least amount of money the class raised. That gets, 28x25 = 700. The class made at least $700.
8 0
3 years ago
Suppose a DVD costs $19 and a CD cost $14. Right in the inequality to find how many CDs you can buy along with one DVD if you ha
andrezito [222]

Answer: 19 + 14x ≤ 65

Explanation:

$19 is only added once because there is only one DVD purchased. $14 is added an unknown number of times, thus the variable X is included. We know that that the total number of dollars spent for both items is either less than or equal to 65. (Depending on your teacher, they may want you to write "19 + 14x < 65" if they want you to write the answer only for discrete numbers).

4 0
1 year ago
1) For question 1, use the figure below. a) Are the following polygons similar? Explain. (2 pts) Yes or No b) Assume the polygon
Delvig [45]

Answer: a) Yes b) Polygon ABCD ~ Polygon EFGH c) JKLM is 3x bigger than polygon ABCD

Step-by-step explanation:

(for part c)

JM= 36

AD= 12

36/12= 3

JKLM is 3x bigger than polygon ABCD

3 0
3 years ago
Please can u answer all the questions!!! Thank u soo much
DiKsa [7]

4.a) 2x=7*3

2x=21

x=21/2 OR

x=10.5

4.b)5x=25*6

5x=150

x=150/5

x=30

4.c)4x=5*14

4x=70

x= 70/4

x=17.5

4.d)4x=9*3

4x=27

X=27/4

X=6.75

4.e)x=0.05*3

X=0.15

4.f)x=0.25*7

X=1.75

4.g)x=0.4*1.5

X=0.6

4.h)x=0.7*2.2

X=1.54

5a)x/7=7-3

X/7=4

X=4*7

X=28

B)2x/5=3+8

2x/5=11

2x=11*5

2x=55

X=55/2

X=27.5

C)2x/3=74-26

2x/3=48

2x=48*3

2x=144

X=72

(I can’t finish all but it is the same method )

5 0
3 years ago
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