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2 years ago

What is the order pairs for (-4,7) , (-6,-4) and (15,8) , (-17,9)

Mathematics

1 answer:

GuDViN [60]2 years ago

4 0

(-4,7) , (-6,-4) and (15,8) , (-17,9)

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Age at BBM 2019 Question Group 'A Brief answer questions; 1. Integrate the following: S(ax? + 2bx + c)3/2(2xa + 2b) dx 2.

worty [1.4K]

If the integral is

$\displaystyle \int (ax^2+2bx+c)^{3/2}(2ax+2b)\,\mathrm dx$

substitute $u = ax^2+2bx+c$ and $\mathrm du=(2ax+2b)\,\mathrm dx$ . Then you end up with

$\displaystyle \int u^{3/2}\,\mathrm du = \frac25u^{5/2} + C$

which in terms of <em>x</em> is

$\boxed{\dfrac25(ax^2+2bx+c)^{5/2} + C}$

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2 years ago

You are going shopping for school supplies. Between what you have saved and what you have been given, you have $300 to use to bu

nydimaria [60]

Answer:

Step-by-step explanation:

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2 years ago

Find the missing probability in the table below.

Alla [95]

X 1 2 3 4
p(x) 0.40 0.20 0.15 ?

If the items are only 4. The total of the probability must be 1 or 100%

1 - 0.40 - 0.20 - 0.15 = 0.25

The probability of 4 is 0.25.

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3 years ago

A student says the prime factors of 17 are 1 and 17

Tju [1.3M]

That is correct as 17 is a prime number and can only be divided by 1 and itself

Hope this helps :)

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3 years ago

Read 2 more answers

Determine the domain of the function (fog) (x) where f(x) = 3x-1/x-4 and g(x)=x+1/x

Mrac [35]

Answer:

$(-\infty,0)\cup(0, \frac{1}{3})\cup (\frac{1}{3},\infty)$

Step-by-step explanation:

The given functions are $f(x)=\frac{3x-1}{x-4}$ and $g(x)=\frac{x+1}{x}$ .

We now composed the two functions to find:

$(f\circ g)(x)=f(g(x))$

$\implies (f\circ g)(x)=f(\frac{x+1}{x})$

$\implies (f\circ g)(x)=\frac{3(\frac{x+1}{x})+1}{\frac{x+1}{x}-4}$

$\implies (f\circ g)(x)=\frac{4x+3}{1-3x}$

This function is defined if the denominator is not zero.

$1-3x\ne0$

$x\ne\frac{1}{3}$

We write this in interval notation as:

$(-\infty,\frac{1}{3})\cup (\frac{1}{3},\infty)$

We need to be cautious here as x=0 is not in the domain of g(x).

Therefore the domain of $(f\circ g)(x)$ is

$(-\infty,0)\cup(0, \frac{1}{3})\cup (\frac{1}{3},\infty)$

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2 years ago

What is the order pairs for (-4,7) , (-6,-4) and (15,8) , (-17,9)​

What is the order pairs for (-4,7) , (-6,-4) and (15,8) , (-17,9)