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3 years ago

Help me!!!!!!!!!!!!!

Mathematics

2 answers:

irakobra [83]3 years ago

8 0

Seven twenty-two am
7:22am

DerKrebs [107]3 years ago

3 0

He arrived at 7:22 because 5:00 +2:22=7:22

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Evaluate the radical.<br> (Look at the photo)<br> Enter your answer in the box.

faltersainse [42]

Answer:

Step-by-step explanation:

This is a cube root so think what times what times what is 27?

3 x 3 x 3 = 27 so the answer is 3

Same problem explained

https://www.mathsisfun.com/numbers/cube-root.html < in detail.

Very helpful website check it out

(It's not a random download link or whatever, look at my profile- i dont do that, its completely safe and legit.)

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3 years ago

Decrease £120 by 45%

Dovator [93]

120 * 45 % = 120 *0,45 = 54 £

120 -54 = 66 £

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3 years ago

Read 2 more answers

Tomika owns 3/5 of a law partnership. What percent of the partnership does she own

harina [27]

3 divided by 5 = 0.6%

5 0

3 years ago

Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used.

astra-53 [7]

Answer:

$3\pi \rightarrow y=2\cos \dfrac{2x}{3}\\ \\\dfrac{2\pi }{3}\rightarrow y=6\sin 3x\\ \\\dfrac{\pi }{3}\rightarrow y=-3\tan 3x\\ \\10\pi \rightarrow y=-\dfrac{2}{3}\sec \dfrac{x}{5}$

Step-by-step explanation:

The period of the functions $y=a\cos(bx+c)$ , $y=a\sin(bx+c)$ , $y=a\sec (bx+c)$ or $y=a\csc(bx+c)$ can be calculated as

$T=\dfrac{2\pi}{b}$

The period of the functions $y=a\tan(bx+c)$ or $y=a\cot(bx+c)$ can be calculated as

$T=\dfrac{\pi}{b}$

A. The period of the function $y=-3\tan 3x$ is

$T=\dfrac{\pi}{3}$

B. The period of the function $y=6\sin 3x$ is

$T=\dfrac{2\pi}{3}$

C. The period of the function $y=-4\cot \dfrac{x}{4}$ is

$T=\dfrac{\pi}{\frac{1}{4}}=4\pi$

D. The period of the function $y=2\cos \dfrac{2x}{3}$ is

$T=\dfrac{2\pi}{\frac{2}{3}}=3\pi$

E. The period of the function $y=-\dfrac{2}{3}\sec \dfrac{x}{5}$ is

$T=\dfrac{2\pi}{\frac{1}{5}}=10\pi$

5 0

3 years ago

An electronic device factory is studying the length of life of the electronic components they produced. The manager selects two

Temka [501]

Answer:

The confidence interval will be given by:

$200000 \pm 44.72z$ , in which z is related to the confidence level.

For a confidence level of x%, z is the value in the z-table that has a pvalue of $1 - \frac{1 - z}{2}$

Step-by-step explanation:

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In the context of this problems:

It means that the sampling distributions of the sample mean of 500 components will be approximated normal, with mean 200,000 and standard deviation $s = \frac{1000}{\sqrt{500}} = 44.72$

To build the confidence interval:

The confidence interval for the average length of life of the electronic components they produced will be given by:

$200000 \pm 44.72z$ , in which z is related to the confidence level.

For a confidence level of x%, z is the value in the z-table that has a pvalue of $1 - \frac{1 - z}{2}$

3 0

3 years ago