Question

Put 3x+12y=-96 into slope intercept form

Answer 1

Answer:

y =-1/4x -8

Step-by-step explanation:

3x+12y=-96

Slope intercept form is y = mx +b where m is the slope and b is the y intercept

Subtract 3x from each side

3x -3x+12y=-3x-96

12y = -3x-96

Divide each side by 12

12y/12 = -3x/12 -96/12

y =-1/4x -8

Answer 2

QUESTION:-

put 3x+12y=-96 into slope intercept form

SOLUTION:-

As we know that,

The slope intercept form:$\pmb{y=mx+c }$

where,

• m=slope
• c=y-intercept

so,

• $\pmb{3x+12y=-96 }$

• $\pmb{12y=-3x-96 }$

• $\pmb{y=\dfrac{-3x-96}{12} }$

• $\pmb{y=\dfrac{-3x}{12}-\dfrac{96}{12} }$

• $\pmb{y=-\dfrac{1}{4}x-8 }$