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Serhud [2]
2 years ago
8

Put 3x+12y=-96 into slope intercept form

Mathematics
2 answers:
RideAnS [48]2 years ago
6 0

Answer:

y =-1/4x -8

Step-by-step explanation:

3x+12y=-96

Slope intercept form is y = mx +b where m is the slope and b is the y intercept

Subtract 3x from each side

3x -3x+12y=-3x-96

12y = -3x-96

Divide each side by 12

12y/12 = -3x/12 -96/12

y =-1/4x -8

Temka [501]2 years ago
5 0
<h3>QUESTION:-</h3>

<em>put 3x+12y=-96 into slope intercept form</em>

<h3>SOLUTION:-</h3>

As we know that,

The slope intercept form:\pmb{y=mx+c }

where,

  • m=slope
  • c=y-intercept

so,

  • \pmb{3x+12y=-96 }

  • \pmb{12y=-3x-96 }

  • \pmb{y=\dfrac{-3x-96}{12} }

  • \pmb{y=\dfrac{-3x}{12}-\dfrac{96}{12} }

  • \pmb{y=-\dfrac{1}{4}x-8 }
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Work Shown:

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Step-by-step explanation:

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